Answer:
D. Fourth example.
Explanation:
In a function, you cannot have two of the same x values, and since 3 and 5 go to two different y values, this cannot be a function.
Hope this helps :)
Answer:
44x + 54
Step-by-step explanation:
The nth term of an arithmetic sequence is given by :
Tn = a + (n - 1)d
d = common difference = T2 - T1
d = T2 - T1
a = first term = - x + 9
d = 4x + 14 - (-x + 9)
d = 4x + 14 + x - 9
d = 5x + 5
The 10th term:
T(10) = (-x + 9) + (10 - 1)*(5x + 5)
T(10) = - x + 9 + 9(5x + 5)
T(10) = - x + 9 + 45x + 45
T(10) = 44x + 54
Hence, the 10th term is 44x + 54
Answer:
B . (fog)(-4) = - 61
Step-by-step explanation:
Here, given f(x) = 4 x + 7, g(x) = 3 x- 5
Now, by the COMPOSITE FUNCTION:
(f o g) (x) = f (g(x))
Now here: )f o g) ( -4) = f (g(-4))
<u>Simplifying for g(x) = 3 x - 5</u>
g(-4) = 3 (-4) - 5 = -12 - 5 = -17
or, g (-4) = -17
Now, <u>for f(x) = 4 x + 7 </u>
f ( g(-4)) = f ( -17) = 4 (-17) + 7
= - 68 + 7 = - 61
or, f ( g(-4)) = - 61
Hence, (fog)(-4) = - 61
ANSWER:
A and B aren't parallel lines, as the alternate angles aren't equivalent to each other.
For m angle 1 -
Vertically opposite angles are equivalent to each other.
m angle 1 is vertically opposite m angle 4.
Therefore:
m angle 4 = 100
m angle 1 = m angle 4
m angle 1 = 100
For m angle 6 -
Co-interior angles add up to 180°.
m angle 4 and m angle 6 are co-interior angles.
Therefore:
m angle 4 = 100
m angle 4 + m angle 6 = 180
100 + m angle 6 = 180
m angle 6 = 180 - 100
m angle 6 = 80
For m angle 7 -
Vertically opposite angles are equivalent to each other.
m angle 6 is vertically opposite m angle 7.
Therefore:
m angle 6 = 80
m angle 7 = m angle 6
m angle 7 = 80
For m angle 8 -
Corresponding angles are equivalent to each other.
m angle 8 and m angle 4 are corresponding angles.
Therefore:
m angle 4 = 100
m angle 8 = m angle 4
m angle 8 = 100
Hence, the angles are as follows:
m angle 1 = 100
m angle 6 = 80
m angle 7 = 80
m angle 8 = 100
Hope this helps! <3
The scientist would use milligrams, grams, and kilograms.
The best procedure would be to randomly pick 52 fish from the entire pond and weigh each of them as this would be the most unbiased way to achieve the average mass
