9514 1404 393
Answer:
D
Step-by-step explanation:
The coefficient of 5/4 in the given equation tells you that you are looking for a table or graph that has a y-increase of 5 for each x-increase of 4.
Graph D is the one.
__
Let's look at the choices:
A: y increases for an x-increase of 4
B. y increases 16 (from -7 to 9) for an x-increase of 4 (from -2 to 2)
C. y increases -5 (from -9 to -14) for an x-increase of 4 (from 4 to 8)
D. y increases 5 (from -2 to 3) for an x-increase of 4 (from -4 to 0)
Answer:
In 5:
UM and MS are equal since the diagonals US and VT have perpendicularly bisected each other.
So,15=6x-3
15+3=6x
18=6x
3=x
In 6:
ET=TC
8=x-4
8+4=x
12=x
The scale factor for area is the square of the scale factor for linear dimensions. If linear dimensions are scaled up by a factor of 10, the area is scaled up by a factor of 10² = 100.
The area of the larger box is 100×432 cm² = 43,200 cm².
Answer:
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Step-by-step explanation:
This question is incomplete
Complete Question
The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.
Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?
Answer:
300 times
Step-by-step explanation:
From the above question, we are told:
The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.
We create a proportion
2 × 10^-1 mg of gold : 6 × 10^1 mg of aluminum
= 0.2 mg of gold : 60 mg of aluminum
Therefore, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body is calculated as:
60mg ÷ 0.2 mg
= 300
Therefore, the number of milligrams of aluminum in the body is 300 times the number of milligrams of gold in the body