3 years ago

How many pentagons can be drawn by joining the vertices of a polygon with 10 sides?

Mathematics

1 answer:

inn [45]3 years ago

5 0

..............10c5..............

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Help me with #22 Please i need steps too

VladimirAG [237]

Answer:

$\frac{1}{2} (8)(x+4)=3(x+6)\\x=2$

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$\frac{1}{2} bh=bh\\\\\frac{1}{2}(8)(x+4)=3(x+6)\\4(x+4)=3x+18\\4x+16=3x+18\\4x=3x+2\\x=2$

1. set the equation for the area of each shape equal to each other

2. simplify each side until you get $4x+16=3x+18$

3. subtract 16 from both sides which will give you $4x=3x+2$

4. subtract 3x from both sides which will give you the value of x. $x=2$

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$area=3(2+6)\\area=3(8)\\area=24$

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