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2 years ago

a girl that is 5 ft tall casts a shadow 4 ft long. At the same time, a tree casts a shadow 24 ft long. How tall is the tree

Mathematics

1 answer:

lara [203]2 years ago

5 0

Answer:

23ft long?????????????????

Step-by-step explanation:

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the area of rectangle a is 11/12 square meters. the area of rectangle b is 8/12 square meters. how much larger is rectangle a?

tresset_1 [31]

11 / 12 - 8 / 12 = 3 / 12 = 1/4 square meters;

5 0

2 years ago

Someone please help me !!! i need it by 7:30!! ammm!!!

AveGali [126]

Answer:

LON and MLN are both equal to 126 degrees,

since the angles with the value '4x + 7' and '7x - 35' degrees are equal to each other, you can rewrite it like this:

4x+7=7x-35

now, take the 7x away from both sides:

-3x+7=-35

then, subtract 7 from both sides:

-3x=-42

now, divide both sides by -3:

x=14

now that we know the value of x (14), we can plug it into the expressions.

4(14)+7=63

7(14)=63

add them together to find the angle MLN

and since the opposite angle (LON) is equal to MLN, they both = 126 degrees

hope this helped :)

8 0

1 year ago

What is the square root of 124.9924

Thepotemich [5.8K]

The answer is:
11.18
Hope This Helps!!
:)

4 0

2 years ago

a 2-month membership to the gym cost $125 jim would like to be a member for 8 months what is the total amount he will pay for 8

Natasha2012 [34]

Answer:

500

Step-by-step explanation:

125 x 4

8 0

2 years ago

100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

4 0

2 years ago

Read 2 more answers