I believe it’s problem solving.
In python 3.8:
user_input = input().split()
x = user_input[0]
char = user_input[-1]
for w in range(1,int(x)+1):
if char in user_input[w]:
print(user_input[w])
I hope this helps
The answer is Fourth-generation language (4GL). <span>Sql is an example of a 4GL category programming language. </span>SQL<span> is considered a Fourth-generation </span>language<span> (</span>4GL), whereas Java and C++ are third-generation languages<span> (3GLs). Fourth-generation </span>languages<span> are programming </span>languages<span> that are closer to human </span>language<span> than the high-level </span>languages<span> like Java.</span>
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
