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Inga [223]
3 years ago
5

Gaff has used 331/3 of his monthly minutes on his cell phone plan. If he already used 200 mintues, how many does he have left th

is month?
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

The first step to solve this problem is to compute for the total minutes allowable in his cell phone plan. To compute for this, you have to divide the number of minutes consumed by the fraction of the time consumed.

200 minutes / 33 1/3% = 600 minutes

To compute for the remaining minutes left for this month, you have to deduct the consumed minutes to the total allowable minutes in his plan.

600 minutes – 200 minutes = 400 minutes left

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Use the quadratic formula to solve for x.<br> 3x2 + 2x - 6 = 0
Daniel [21]

Answer:

x = 1/3 (sqrt(19) - 1) or x = (1/3 (-1 - sqrt(19)))

Step-by-step explanation:

Solve for x over the real numbers:

3 x^2 + 2 x - 6 = 0

Using the quadratic formula, solve for x.

x = (-2 ± sqrt(2^2 - 4×3 (-6)))/(2×3) = (-2 ± sqrt(4 + 72))/6 = (-2 ± sqrt(76))/6:

x = (-2 + sqrt(76))/6 or x = (-2 - sqrt(76))/6

Simplify radicals.

sqrt(76) = sqrt(4×19) = sqrt(2^2×19) = 2sqrt(19):

x = (2 sqrt(19) - 2)/6 or x = (-2 sqrt(19) - 2)/6

Factor the greatest common divisor (gcd) of -2, 2 sqrt(19) and 6 from -2 + 2 sqrt(19).

Factor 2 from -2 + 2 sqrt(19) giving 2 (sqrt(19) - 1):

x = 1/6(2 (sqrt(19) - 1)) or x = (-2 sqrt(19) - 2)/6

In (2 (sqrt(19) - 1))/6, divide 6 in the denominator by 2 in the numerator.

(2 (sqrt(19) - 1))/6 = (2 (sqrt(19) - 1))/(2×3) = (sqrt(19) - 1)/3:

x = (1/3 (sqrt(19) - 1)) or x = (-2 sqrt(19) - 2)/6

Factor the greatest common divisor (gcd) of -2, -2 sqrt(19) and 6 from -2 - 2 sqrt(19).

Factor 2 from -2 - 2 sqrt(19) giving 2 (-sqrt(19) - 1):

x = 1/3 (sqrt(19) - 1) or x = 1/6(2 (-1 - sqrt(19)))

In (2 (-sqrt(19) - 1))/6, divide 6 in the denominator by 2 in the numerator.

(2 (-sqrt(19) - 1))/6 = (2 (-sqrt(19) - 1))/(2×3) = (-sqrt(19) - 1)/3:

Answer:  x = 1/3 (sqrt(19) - 1) or x = (1/3 (-1 - sqrt(19)))

4 0
2 years ago
Which expression is equivalent to the following complex fraction? 2 minus StartFraction 1 Over y EndFraction divided by 3 StartF
Leya [2.2K]

The equivalent fraction to the given complex fraction is  \frac{2y-1}{3y+1}.

Given expression,

\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} } } \\

We have to find the equivalent fraction of    \frac{2-\frac{1}{y} }{3+\frac{1}{y} } } \\ .

On solving,

\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} } } =\dfrac{\frac{2y-1}{y} }{\frac{3y+1}{y} }

Eliminating y from numerator and denominator we get,

\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} } } =\dfrac{2y-1} {3y+1} }

Hence the required expression is    \frac{2y-1}{3y+1}.

For more details follow the link:

brainly.com/question/17912

8 0
2 years ago
Read 2 more answers
On a map, 1 inch equals 15 miles. Two cities are 7 inches apart on the map. What is the actual
Otrada [13]

Answer:

105 miles

Step-by-step explanation:

The ratio you have is 1:15

So you must multiply 7 by 15 to find the actual distance in miles.

7*15=105

4 0
3 years ago
Identify a pattern in this list of numbers. Then use this pattern to find the next number.​ (More than one pattern might​ exist,
kicyunya [14]

Answer:

<em>a)   45</em>

<em>The sequence  3 , 5, 9 , 15 , 23 , 33 , 45</em>

Step-by-step explanation:

<em>Given The sequence  3 , 5, 9 , 15 , 23 , 33 </em>

<em>First term = 3</em>

<em>Add 2  of first term   </em>

<em>Second term  = 3 +2 = 5</em>

<em>Add 4  of second term   </em>

<em>Third term = 5 + 4 = 9</em>

<em>Add 6  of Third term   </em>

<em>Fourth term  = 9 + 6 = 15</em>

<em>Add 8 of  fourth term</em>

<em>fifth term = 15 + 8 = 23</em>

<em>Add 10 of fifth term </em>

<em>sixth term = 23 + 10 = 33</em>

<em>Add 12 of sixth term</em>

<u><em>seventh term = 33 +12 = 45</em></u>

<u><em>Final answe</em></u><em>r:-</em>

<em>Now the sequence   3​, 5​, 9​, 15​, 23​, 33​, ​__45___</em>

<em></em>

3 0
3 years ago
Write the expression in standard form. 3 + (2− 4)
Liono4ka [1.6K]

Answer:

3 + 2 - 4 = ?

Step-by-step explanation:

7 0
3 years ago
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