Find the first derivatives:
.
Solve the system
:
. The second equation has solutions
and then
and you have two points
.
Find the first derivatives:
and calculate
![\Delta=\left| \left[\begin{array}{cc}24&-24\\-24&12y\end{array}\right]\right |=24\cdot 12y-(-24)^2=288y-576](https://tex.z-dn.net/?f=%5CDelta%3D%5Cleft%7C%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D24%26-24%5C%5C-24%2612y%5Cend%7Barray%7D%5Cright%5D%5Cright%20%7C%3D24%5Ccdot%2012y-%28-24%29%5E2%3D288y-576)
.
Since
and
,
is a point of maximum and
.
Since
and
,
is a point of minimum and
.
Degree is the value of the highest power of the variable, and hence in this case is 8
Answer:
It is false
Step-by-step explanation:
It is false because 12 has the factors of 2 and 4 but 8 is not a factor of 12.
Answer:
Y =-4X +12
Y =-0.625X -0.75
Step-by-step explanation:
(3,0) and (2,4)....
x1 y1 x2 y2
3 0 2 4
(Y2-Y1) (4)-(0)= 4 ΔY 4
(X2-X1) (2)-(3)= -1 ΔX -1
slope= -4
B= 12
Y =-4X +12
~~~~~~~~~~~~~~~~~
(-6,3) and (2,-2)
x1 y1 x2 y2
-6 3 2 -2
(Y2-Y1) (-2)-(3)= -5 ΔY -5
(X2-X1) (2)-(-6)= 8 ΔX 8
slope= - 5/8
B= - 3/4
Y =-0.625X -0.75
Answer:
70/5985
Step-by-step explanation:
We know that a quadrilateral needs to have four vertices (or points on the circle). There are always two ways to link the cross — horizontally or vertically. Using my limited knowledge of combinations, we know that choosing four points out of seven equals 35. Multiplying the two ways to connect those lines (again, horizontally and vertically) makes 35*2 = 70 "bow-tie quadrilaterals" that can be formed on the circle using four points. There are 5985 ways four chords can be chosen out of twenty-five chords because C(25,4) equals 5985, so the probability is 70/5985... and then we just need to simplify that fraction.
