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Dovator [93]
2 years ago
10

Use the quadratic formula to solve for x. 3x2 + 2x - 6 = 0

Mathematics
1 answer:
Daniel [21]2 years ago
4 0

Answer:

x = 1/3 (sqrt(19) - 1) or x = (1/3 (-1 - sqrt(19)))

Step-by-step explanation:

Solve for x over the real numbers:

3 x^2 + 2 x - 6 = 0

Using the quadratic formula, solve for x.

x = (-2 ± sqrt(2^2 - 4×3 (-6)))/(2×3) = (-2 ± sqrt(4 + 72))/6 = (-2 ± sqrt(76))/6:

x = (-2 + sqrt(76))/6 or x = (-2 - sqrt(76))/6

Simplify radicals.

sqrt(76) = sqrt(4×19) = sqrt(2^2×19) = 2sqrt(19):

x = (2 sqrt(19) - 2)/6 or x = (-2 sqrt(19) - 2)/6

Factor the greatest common divisor (gcd) of -2, 2 sqrt(19) and 6 from -2 + 2 sqrt(19).

Factor 2 from -2 + 2 sqrt(19) giving 2 (sqrt(19) - 1):

x = 1/6(2 (sqrt(19) - 1)) or x = (-2 sqrt(19) - 2)/6

In (2 (sqrt(19) - 1))/6, divide 6 in the denominator by 2 in the numerator.

(2 (sqrt(19) - 1))/6 = (2 (sqrt(19) - 1))/(2×3) = (sqrt(19) - 1)/3:

x = (1/3 (sqrt(19) - 1)) or x = (-2 sqrt(19) - 2)/6

Factor the greatest common divisor (gcd) of -2, -2 sqrt(19) and 6 from -2 - 2 sqrt(19).

Factor 2 from -2 - 2 sqrt(19) giving 2 (-sqrt(19) - 1):

x = 1/3 (sqrt(19) - 1) or x = 1/6(2 (-1 - sqrt(19)))

In (2 (-sqrt(19) - 1))/6, divide 6 in the denominator by 2 in the numerator.

(2 (-sqrt(19) - 1))/6 = (2 (-sqrt(19) - 1))/(2×3) = (-sqrt(19) - 1)/3:

Answer:  x = 1/3 (sqrt(19) - 1) or x = (1/3 (-1 - sqrt(19)))

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Temka [501]

x = player1

y = player 2

z = player 3

y = 2x  or 1/2 y =x

y = z-10  or z = y+10

x+y+z=70

substitute x= 1/2 y and z = y+10 into the above equation

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subtract 10 from each side

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y =24

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The three players scored 12, 24, 34


4 0
3 years ago
Read 2 more answers
Number 2 please thanks
Alex

Answer:

c) 2x+1

Step-by-step explanation:

Let's x be number of Nick's goals.

Emma has scored 1 more than twice the number of Nicks.

1 more is +1, of twices the number is 2x.

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6 0
3 years ago
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stellarik [79]
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3 years ago
Working with Laws and of Sines and Cosines.
malfutka [58]
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a = 
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Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 

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