The examples where using conservation of energy to solve a problem is easier than other methods are:
1. Pendulum
2. Nuclear Power Plant
The principle of the conservation of energy says that:
Energy within an isolated system is neither created nor destroyed, it simply changes from one type of energy to another.
1. Pendulum:
As the pendulum swings down:
gravitational potential energy of the pendulum →kinetic energy of the pendulum.
As the pendulum swings up: kinetic energy of the pendulum→ gravitational potential energy of the pendulum.
2. Nuclear Power Plant:
Nuclear energy (from the decay of uranium) → thermal energy of water
→kinetic energy of a turbine →electrical energy + thermal energy (from friction in the turbine and transmission lines)
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Answer:
Explanation:
The work-energy theorem states that the work done on the system is equal to its change of kinetic energy: . This refers to the center of mass in the case of a system of particles. To calculate this work, we need to use the net Force on the system and the displacement of its center of mass:
Answer: Efficiency signifies a peak level of performance that uses the least amount of inputs to achieve the highest amount of output.
Explanation: It minimizes the waste of resources such as physical materials, energy, and time while accomplishing the desired output.
Answer:
(a) λ= 0.603m
(b) v= 50.8329
(c)
Explanation:
(a)The string is an open pipe and five loops indicates that the wave forms three complete cycle in the string.
A circle represents 1 wavelength. The loops occupy the whole length of the pipe, hence;
3λ = 1.81m
λ=
λ= 0.603m
(b) speed(v) = fλ
v= 84.3 * 0.603
v= 50.8329
(c) The string represents an open pipe.for an open pipe, the fundamental frequency is
First let us calculate for the angle of inclination using
the sin function,
sin θ = 1 m / 4 m
θ = 14.48°
Then we calculate the work done by the movers using the
formula:
W = Fnet * d
So we must calculate for the value of Fnet first. Fnet is
force due to weight minus the frictional force.
Fnet = m g sinθ – μ m g cosθ
Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48
Fnet = 84.526 N
So the work exerted is equal to:
W = 84.526 N * 4 m
<span>W = 338.10 J</span>