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Julli [10]
3 years ago
13

For every particle there is a corresponding ______________.

Physics
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

Anti-Particle

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a light bulb has a resistance of 360 . what is the current in the bulb when it has a potential difference of 120 v across it? 0.
xenn [34]
Presume we are looking for the current:

V = IR

120 = I*360

120/360 = I

1/3 = I

I = 1/3 = 0.333..

Current ≈ 0.33 Ampere.
7 0
3 years ago
Read 2 more answers
Arrange the following types of photons of electromagnetic radiation in order of decreasing energy: red light, radio, x-rays, γ-r
MrRa [10]

Answer:The correct order is

γ-rays > x-rays> red light > infrared > radio

Explanation:

In the electromagnetic spectrum we have the following electromagnetic radiation Radio waves, infrared radiation, visible light, ultraviolet light, X-ray and gamma rays. Gamma rays have the highest  frequency and radio waves the lowest. From the formula;

E=hf,      where;

E is energy

h is Planck constant

f is frequency

We can see that the energy of these radiation depends on the magnitude of their frequency. Hence Gamma ray with highest frequency will have the highest energy and radio waves the lowest energy. Red light however is found at the lower end of the visible light spectrum . the correct order is;

γ-rays > x-rays> red light > infrared > radio

8 0
3 years ago
If you increase the frequency of a sound wave four times, what will happen to its speed?
ozzi

The speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

<h3>How to calculate the frequency of a wave.</h3>

Mathematically, the frequency of a sound wave is given by this formula:

F = \frac{V}{\lambda}

<u>Where:</u>

  • F is the frequency of a sound wave.
  • V is the velocity of a sound wave.
  • \lambda is the wavelength of a sound wave.

<u>Note:</u> The frequency of the sound wave is increased four (4) times.

  • F = 4F

Substituting the given parameters into the formula, we have;

4F = \frac{V}{\lambda}\\\\V=4F\lambda

Therefore, the speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

Read more on sound wave here: brainly.com/question/19250621

4 0
3 years ago
7) the observation deck of the Empire State Building is 381 m above the street. Determine the
Elan Coil [88]

Answer:

Questions involving accelerating objects, including those in free fall, can be solved using three equations

 

y =  1/2at2 + v0t + y0

 

v = v0 + at

 

vf2 = v02 + 2 a (y - y0)

 

In this case, only the first equation is needed.

 

Since the object is falling the final height is 0 meters, the initial height is 370 m, and the acceleration is -9.8ms-2

 

Since the object is dropped, the initial velocity is 0.

 

0 = 1/2(-9.8)t2 + 370.    t = sqrt(370/4.9) = 8.69 s

Explanation:

8 0
4 years ago
Read 2 more answers
3. Suppose that an airplane flying 60 m/s, at a height of 300m, dropped a sack of flour (pere the effect
Arlecino [84]

469.24m. An airplane flying 60m/s at a height of 300m dropped a sack of flour that stack the ground 469.24m from the point of release.

This is a example of horizontal parabolic projectile motion,and we represents this motion in the coordinate axis, which means that the velocity has components in x axis and y axis.

The equation of components on the x axis.

v_{0}x=\frac{x}{t}, where x is the distance and Vox the initial velocity before the drop

The equation of components on the y axis.

y = v_{0}yt+\frac{gt^{2} }{2}, where y is the height, and the velocity in y component before the drop is 0, reducing the equation to y = \frac{gt^{2} }{2}

Clear t from both the equation of components on the x axis and the y axis:

t=\frac{x}{v_{0} x} and t=\sqrt{\frac{2h}{g}}

Equating both equations and clearing the distance x:

\frac{x}{v_{0} x}=\sqrt{\frac{2h}{g}}\\x={v_{0} x}\sqrt{\frac{2h}{g}}

Substituting the values:

x=60\frac{m}{s} \sqrt{\frac{2(300m)}{9.81\frac{m}{s^{2} } }}=469.24m

3 0
3 years ago
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