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3 years ago

Pllllllease help me asap

Mathematics

1 answer:

marishachu [46]3 years ago

4 0

Answer & Step-by-step explanation:

When we see the phrase "rate of change" then it means that we are looking for the slope. So, we will need to know the formula for finding slope or the rate of change.

$slope=\frac{y_2-y_1}{x_2-x_1}$

Now, let's use this equation to solve for the rate of change of each question.

Problem 1:

$Slope=\frac{2-\frac{4}{3}}{0-(-1)}\\\\Slope=\frac{\frac{2}{3}}{1}\\\\Slope=\frac{2}{3}$

The rate of change of this equation is 2/3

Problem 2:

$Slope=\frac{4-2}{1-0}\\\\Slope=\frac{2}{1}\\\\Slope=2$

The rate of change for this equation is 2

Problem 3:

$Slope=\frac{10-4}{2-1}\\\\Slope=\frac{6}{1}\\\\Slope=6$

The rate of change for this equation is 6

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In a study of academic procrastination, the authors of a paper reported that for a sample of 471 undergraduate students at a mid

AnnZ [28]

Answer:

95% confidence interval for the mean time spent studying for the final exam for students taking introductory psychology at this university is [6.85 hours, 7.43 hours].

Step-by-step explanation:

We are given that a sample of 471 undergraduate students at a midsize public university preparing for a final exam in an introductory psychology course, the mean time spent studying for the exam was 7.14 hours and the standard deviation of study times was 3.20 hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time spent studying for the exam = 7.14 hours

$\sigma$ = population standard deviation = 3.20 minutes

n = sample of undergraduate students = 471

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $7.14-1.96 \times {\frac{3.20}{\sqrt{471} } }$ , $7.14+1.96 \times {\frac{3.20}{\sqrt{471} } }$ ]

= [6.85 hours , 7.43 hours]

Therefore, 95% confidence interval for the mean time spent studying for the final exam for students taking introductory psychology at this university is [6.85 hours, 7.43 hours].

7 0

3 years ago

PLS HELP ME I WILL MARK!!!!~ don't need to show work

Sauron [17]

I’m not so sure, but I think it might be:
f(x)=x-1
Sorry if wrong

6 0

3 years ago

Read 2 more answers

How many 0.75 pound packages can you make with 9 pounds of popcorn

Paul [167]

Answer:

Step-by-step explanation: