Answer:
The 95% confidence interval for the measurements is [48.106, 53.494].
Step-by-step explanation:
The average M of this sample is
The standard deviation s of this sample is
![s=\sqrt{\dfrac{1}{4}\cdot [(52-50.8)^2+(48-50.8)^2+(49-50.8)^2+(52-50.8)^2+(53-50.8)^2]}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%2852-50.8%29%5E2%2B%2848-50.8%29%5E2%2B%2849-50.8%29%5E2%2B%2852-50.8%29%5E2%2B%2853-50.8%29%5E2%5D%7D)
![s=\sqrt{\dfrac{1}{4}\cdot [(1.44)+(7.84)+(3.24)+(1.44)+(4.84)]}=\sqrt{\dfrac{18.8}{4}}=\sqrt{4.7}\\\\\\s=2.168](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%281.44%29%2B%287.84%29%2B%283.24%29%2B%281.44%29%2B%284.84%29%5D%7D%3D%5Csqrt%7B%5Cdfrac%7B18.8%7D%7B4%7D%7D%3D%5Csqrt%7B4.7%7D%5C%5C%5C%5C%5C%5Cs%3D2.168)
The degrees of freedom are
Then, the critical value of t for a 95% CI and 4 degrees of freedom is t=2.776.
The margin of error of the CI is:
Then, the lower and upper bounds of the CI are:
The 95% confidence interval for the measurements is [48.106, 53.494].
The answer is x=6
hope this helps!
Answer: The answer would be the second one.
Step-by-step explanation:
It is hard to explain but, I made and equation that would go with the problem which would be 2 points for every goal plus the free goals for every goal. (2g+f) and in then end it should all equal 15 so the equation so far would be 2g+f =15. This then leave you with three answers left. then I had plugged in a random number to solve it. g and f exacly should be the same number because for every goal you get a free point so if you get one goal then one extra point, if three goals then three extra points. so if you plug in 5 then 2 times 5 plus 5 is 15. The similarities between g and f is if you subtract them it is always going to be zero. Which makes the second answer correct for this problem.
Answer:
b
Step-by-step explanation:
