The vertex is at (2, 5).
To find the vertex, we first find the axis of symmetry; this is given by
x = -b/2a
For our equation, b = -16 and a = 4:
x = -(-16)/2(4) = 16/8 = 2
We substitute this back into our equation:
y = 4(2)² - 16(2) + 21 = 4(4) - 32 + 21 = 5
Therefore the vertex is at (2, 5).
Changing g(x) to this form: a(x-h) + k, we have:
g(x) = 4 (x+3)^2 - 6
Comparing this to the original equation, f(x) = x^2, we have the following transformations:
The graph is widened.
The graph is shifted left 3 units.
7 ig because I mean if you take a look at the problem
Answer:
B
Step-by-step explanation:
Assuming the dilatation is centred at the origin, then multiply each of the coordinates by 4 , that is
A (0, 10 ) → A' (4(0), 4(10) ) → A' (0, 40 )
B (8, 6 ) → B' (4(8), 4(6) ) → B' (32, 24 )
C (4, 2 ) → C' (4(4), 4(2) ) → C' (16, 8 )
Answer:
There are 5 theorem to prove the triangles are congruent. They are:
