Since b is the midpoint BC is half the line so we can set up this equation
x+4+X+4=3x-8
and then solve like normal
2x+8=3x-8
16=x
once you have x then solve x+4
16 + 4 =20
AB is 20
x =(-4-√96)/40=(-1-√ 6 )/10= -0.345
:)
there are 8 numbers and you want to get either a 3 or an 8
3 or 8 is 2 numbers out of the 8
so you have a 2/8 reduced to a 1/4 probability of getting them.
We know, equation of ellipse is given by :

Here,
(h,k) is centre of the ellipse = (0,0).
a = major axis = 8.
b = minor axis = 4.
Putting all given value in above equation, we get :

Hence, this is the required solution.
Answer:
Step-by-step explanation:
Center (0,0)
radius = √16 = 4