I believe the answer is e
The differential equation
is considered exact if (where subscripts denote partial derivatives). If it is exact, then its general solution is an implicit function such that and .
We have
and , so the equation is indeed exact.
Now, the solution satisfies
Integrating with respect to , we get
and differentiating with respect to , we get
Then the general solution to the exact equation is
Answer:
f(g(x)) = 15x + 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
- Functions
- Function Notation
- Composite Functions
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = 5x + 7
g(x) = 3x - 1
<u>Step 2: Find</u>
- Substitute in functions: f(g(x)) = 5(3x - 1) + 7
- [Distributive Property] Distribute 5: f(g(x)) = 15x - 5 + 7
- [Addition] Combine like terms: f(g(x)) = 15x + 2
Answer:
A
Step-by-step explanation:
I know that 20 times 7 is 140 and if I take away 2 sevens that leaves 126. So 126 \div 7 = 18