The complement of the given set is:
A* = {-1, 0, 1, 4, 5}
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How to find the complement of the set?</h3>
For any set A on a universal set U, such that:
A ⊂ U.
The complement of A is the set of all the terms on U that do not belong to A.
Here we have:
U = {-3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7}
And the given set is:
A = {-3, -2, 2, 3, 6, 7}
Then the complement of A is:
A* = {-1, 0, 1, 4, 5}
(all the elements of U that are not in A).
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There are 625 different 4-digit codes only made with odd numbers.
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How many different combinations can you make?</h3>
To find the total number of combinations, we need to find the number of options for each one of the digits.
There are 4 digits, such that each digit can only be an odd number.
- For the first digit, there are 5 options {1, 3, 5, 7, 9}
- For the second digit, there are 5 options {1, 3, 5, 7, 9}
- For the third digit, there are 5 options {1, 3, 5, 7, 9}
- For the fourth digit, there are 5 options {1, 3, 5, 7, 9}
The total number of different combinations is given by the product between the numbers of options, so we have:
C = 5*5*5*5 = 625.
There are 625 different 4-digit codes only made with odd numbers.
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X^2-22x-48=0
x^2-24x+2x-48=0
x(x-24)+2(x-24)
(x+2)(x-24)
Solve by grouping if you are able to find distinct factors that multiply to the last term and add to the middle term...this method is rather easy with easy to manage numbers. Complete the square if you cannot find distinct factors that multiply to the last term and add to the middle term. Completing the square helps when the equation is in the form of a parabola.