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Alenkinab [10]
3 years ago
8

Share 150 pounds in the ratio 4:1

Mathematics
1 answer:
daser333 [38]3 years ago
4 0
150 pounds divided into 4:1 ratio means that there are 4+1 = 5 portions.
one quantity is 4 times the amount of the other quantity.
150 can be divided into 5 portions,
therefore 1 portion is =150/5 = 30
First quantity is 4 times the amount of one portion = 4*30 = 120
and other portion is 30 
therefore quantities are divided as 120:30 


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If the flight takes 55 minutes to depart at 11:45 what time is he expecting to arrive at new york
sergiy2304 [10]
We know that
1 hour------> 60 minutes
so

= [11:45 am] + 55 min 

= [11 h + 45 min + 55 min] am 

= [11 h + 100 min] am 

= [11 h + (60 + 40) min] am 

= [11 h + 60 min + 40 min] am → you know that: 60 min = 1 h 

= [11 h + 1 h + 40 min] am 

= [12 h + 40 min] → when you get 12, am → pm 

<span>= 12:40 pm
</span>
the answer is
12:40 pm


3 0
4 years ago
If f(x)=x^2 then what is f(x+h)? an explanation would be lovely, but if not that’s okay :)
Nadusha1986 [10]

Answer: f(\text{x+h}) = \text{x}^2+2\text{x}\text{h}+\text{h}^2

====================================================

Work Shown:

f(\text{x}) = \text{x}^2\\\\f(\text{x+h}) = (\text{x+h})^2\\\\f(\text{x+h}) = (\text{x+h})(\text{x+h})\\\\f(\text{x+h}) = \text{x}*\text{x}+\text{x}*\text{h}+\text{h}*\text{x}+\text{h}*\text{h}\\\\f(\text{x+h}) = \text{x}^2+\text{x}\text{h}+\text{x}\text{h}+\text{h}^2\\\\f(\text{x+h}) = \text{x}^2+2\text{x}\text{h}+\text{h}^2\\\\

Explanation:

I replaced each copy of x with x+h. Then I used the FOIL rule to expand things out and combine like terms. The distributive property or the box method are two other pathways you can take.

8 0
1 year ago
3x + 6 = 12<br><br> What is the 3 called?<br> What is the 6 called?<br> How many terms are there?
asambeis [7]

Answer:

it's like 3x3 and it =6 what 6x6= 36

6 0
3 years ago
How do i rearrange this equation into y=mx+b? y = - x - 5
MissTica

The Solution:

Given:

y=-x-5

Required:

To write the given equation in the form below:

y=mx+b

Clearly, the given equation is already in the required form.

The parameters are:

8 0
2 years ago
Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre
andrew-mc [135]

Answer:

The area function is

A=\frac{135}{2}x-\frac{9}{2}x^2.

The domain and range of A is (0,15m) and (0, 253.125 m^2].

Step-by-step explanation:

The given length of fencing is 90 m.

Let the length and width of each pen be x and y respectively as shown in the figure.

As there are 3 pens, so, the total area,

A= 3 xy \;\cdots (i)

From the figure the total length of fencing is 6x+4y.

Here, for a significant area for the animals, x>0 as well as y>0 as x and y are the sides of ben.

From the given value:

6x+4y=90\;\cdots (ii)

\Rightarrow  y=\frac {45}{2}-\frac{3x}{2}

Now, from equation (i)

A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)

\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)

This is the required area function in the terms of variable x.

For the domain of area function, from equation (ii)

x=15-\frac{2y}{3}

\Rightarrow x [as y>0]

So, the domain of area function is (0,15m).

For the range of area function:

As x \rightarrow 0 or y\rightarrow 0, then A\rightarrow 0 [from equation (i)]

\Rightarrow A>0

Now, differentiate the area function with respect to x .

\frac {dA}{dx}=\frac{135}{2}-9x

Equate \frac {dA}{dx}  to zero to get the extremum point.

\frac {dA}{dx}=0

\Rightarrow \frac{135}{2}-9x=0

\Rightarrow x=\frac{15}{2}

Check this point by double differentiation

\frac {d^2A}{dx^2}=-9

As,  \frac {d^2A}{dx^2}, so, point x=\frac{15}{2} is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2

\Rightarrow A=253.125 m^2

Hence, the range of area function is (0, 253.125 m^2].

4 0
4 years ago
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