Billy plotted −3

Mathematics

2 answers:

nevsk [136]3 years ago

7 0

Answer:

Sample Response: Yes, Billy is correct. The fractions are placed on the correct tick marks. The smaller fraction is located to the left of the larger fraction.

Step-by-step explanation:

andrew11 [14]3 years ago

5 0

Answer:

Yes, he is right. The smaller fraction is located to the left of the larger fraction.

NOT A SAMPLE RESPONSE BUT IS CORRECT!

Step-by-step explanation:

You might be interested in

Find the GCF from the two numbers and rewrite the sum using nthe distributive property

Vadim26 [7]

Answer:

The greatest common factor is 6.

Step-by-step explanation:

Greatest common factor is 6. If you use the distributive property then the answer would be 6(4) + 6(6) or 6(4+6). Then you distribute the 6 to each digit and should get 24+36.

6 0

3 years ago

Mr. Smith baked 144 blueberry pies, some strawberry pies, and some apple pies. The number of apple pies is 4\5 of the number of

Leviafan [203]

B = 144
a = 4/5s
s = a + 24

s = 4/5s + 24
5/5s - 4/5s = 24
1/5s = 24
s = 24 * 5
s = 120

a = 4/5s
a = 4/5(120)
a = 480/5
a = 96

blueberry pies = 144
total of all pies = 144 + 120 + 96 = 360

percent of blueberry pies is : 144/360 = 0.40 = 40% <==

6 0

3 years ago

Read 2 more answers

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$