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4 years ago

Put this distance in order from least to greatest 3/16 miles 1/8 miles 3/4 miles

Mathematics

1 answer:

KATRIN_1 [288]4 years ago

8 0

1/8 miles, 3/16 miles, 3/4 miles

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A circle has a circumference of 6. It has an arc of length 1.

Viktor [21]

Answer:

Step-by-step explanation:

Given that:

Circumference (C) = 6 units
Arc length (A) = 1 unit

<u>Find the central angle (</u><u>θ</u><u>)</u>

Arc is some part of circumference; thus,

the equation of arc length =

A = θ/360 × C

θ/360 = A/C

θ = (360×A)/C

θ = (360×1)/6

θ = 360 ÷ 6

Central angle = 60°

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- kexcvi

8 0

3 years ago

Are AB and CD parallel, perpendicular, or neither?*<br> 1. A(-4, 8), B(4, 10), C(1, 1), D(-2, 13)

ohaa [14]

Answer:

Perpendicular

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Step-by-step explanation:

Given

$A = (-4, 8)$

$B = (4, 10)$

$C = (1, 1)$

$D = (-2, 13)$

Required

Is AB and CD parallel?

First, we need to calculate the slope (m) of AB and CD

$m = \frac{y_2 - y_1}{x_2 - x_1}$

For AB:

$A (x_1,y_1)= (-4, 8)$

$B(x_2,y_2) = (4, 10)$

So:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{10 - 8}{4 - (-4)}$

$m = \frac{10 - 8}{4 +4}$

$m = \frac{2}{8}$

$m = \frac{1}{4}$

For CD:

$C(x_1,y_1) = (1, 1)$

$D(x_2,y_2) = (-2, 13)$

So:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{13 - 1}{-2 - 1}$

$m = \frac{12}{-3}$

$m = -4$

For Lines to be parallel, the slope must be equal:

i.e. $m_1 = m_2$

This condition is not true because:

$\frac{1}{4} \neq -4$

For Lines to be perpendicular, the slope must be:

$m_1 = -\frac{1}{m_2}$

This implies:

$\frac{1}{4} = -\frac{1}{-4}$

$\frac{1}{4} = \frac{-1}{-4}$

$\frac{1}{4} = \frac{1}{4}$

<em>Hence, the lines are perpendicular</em>

6 0

3 years ago

Pleaseee answer 1st correct answer gets brainliest

Ludmilka [50]

Answer:

4. No they do not form a proportion. 5. Yes they do form a proportion

Step-by-step explanation:

4 is less than 7 and 24 is less than 35 so they make proportions.

7.50 is more than 3 and 5 is more than 2 so they do not make proportions.

3 0

3 years ago

Frank says that 50% of a number will always be greater than 20% of any other number. Complete one inequality to support Frank's

Archy [21]

Hi there! I saw your question and decided to help you out.

To support his claim:

50 of 100 and 20 of 100

To debunk his claim:

50 of 10 and 20 of 100

I hope this answers your question !

5 0

3 years ago

Read 2 more answers

Please help me.!

IRINA_888 [86]

You set up a proportion. You would do 1 is to 48 as x is to 300 then u cross multiply and get 48x=300and then do 300/48 and thats 6.25 minutes

5 0

3 years ago