Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
To find x-intercept, put the Y value = 0;
4x - 2y = -12
-> 4x -2.0 = -12
-> 4x = -12
-> x = -12/4
-> x = -3
X-intercept: (-3,0)
Now do the reverse to find the y-intercept, X = 0;
4x - 2y = -12
-> 4.0 - 2y = -12
-> -2y = -12 x(-1)
-> 2y = 12
-> y = 12/2
-> y = 6
Y-intercept: (0, 6)
Answer: I think your answer is 2 ( please let me know if this is wrong ) !
Step-by-step explanation:
let's recall that the vertical asymptotes for a rational expression occur when the denominator is at 0, so let's zero out this one and check.
Answer:
-2
Step-by-step explanation:
2(x-3), x=2
Since we know what x equals, plug it into the equation
2(2-3)
2(-1)
-2
