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3 years ago

Round 23.5584557678 to the nearest hundredth.

1 answer:

4 0

The hundredth is the second number to the right of the decimal point. Also, if the number directly to the right of it is 5 or larger, you will have to round up by one.

23.558 becomes 23.56.

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Can you solve ?<br> |2x-9|=7<br> What is the answer please

Nikitich [7]

Split it into 2 equations
2x-9 = 7
2x = 16
x = 8
And another equation
2x-9 = -7
2x = 2
x = 1
The answer is x =1, x= 8

4 0

3 years ago

You want to order carpet for an area in your house. The room measures 12 feet by 10 feet. The carpet is sold in square yards. Ho

FromTheMoon [43]

Answer:

yards of carpet you need: 4*10/3=40/3=13.3333 yd^2

Step-by-step explanation:

convert feet to yard:

1 yard=3 feet so

12 feet=4 yards

10 feet=10/3 yard=3.33333 yard

yards of carpet you need: 4*10/3=40/3=13.3333 yd^2

3 0

3 years ago

The phone company B-Mobile has a monthly cellular plan where a customer pays a flat fee for unlimited voice calls and then a cer

Oxana [17]

Step-by-step explanation:

That's the rifgt answer for sure!!

Plz Mark brainliest...

6 0

3 years ago

HELP <3 Match the expressions with their solutions.

densk [106]

Answer:

1 ) sin 165°

2 ) cos 330°

3 ) Tan 157.5°

4 ) $sin^2 157.5$

Step-by-step explanation:

1 )

Given expression is $\sqrt{\frac{1-cos330}{2} }$

We know that $cos2x=1-2sinx^{2}$

$sinx^{2}=\frac{1-cos2x}{2}$

$(sinx/2)^2=\frac{1-cosx}{2}$

So the first expression is sin (330/2)° =sin 165°

2 )

GIven expression is $1-2sin^2165$

We know that $cos2x=1-2sinx^{2}$

So the result is cos 330°

3 )

Given expression is $\frac{1-cos 315}{sin315}$

We know that $cos2x=1-2sinx^{2}$

Also we know that sin2x = 2sinxcosx

So The numerator becomes $2sin^2x/2$ . and the denominator becomes as $2sinx/2cosx/2$

$\frac{2sin^2x/2}{2sinx/2cosx/2}=tanx/2$

So the result is Tan 157.5°

4 )

Given expression is $\frac{1-cos 315}{2}$

We know that $cos2x=1-2sinx^{2}$

$(sinx/2)^2=\frac{1-cosx}{2}$

So the result is $sin^2 157.5$

6 0

3 years ago

For a normal distribution, the z value for an x value that is to the right of the mean is always:

Dmitry_Shevchenko [17]

In a normal distribution, the z value for an x value that is to the right of the mean will always be positive while on the other hand if the z value for an x value that is to the left of the mean it will always be negative. It is because left side is always negative and right side is always positive.

7 0

3 years ago