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liubo4ka [24]
3 years ago
14

Find common ratio in the geometric sequence 1,5,25,125

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
You multiply 5 each time
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What two patterns is in the table show
serg [7]

Answer:

X= 25, the second one is 22, the third one is 19

y=20, the second one is 17, the thirst one is 12

The terms in patten y is 5 less than the terms in pattern x

Step-by-step explanation:

3 0
3 years ago
A system of equations is shown below,
Vikki [24]
Answer: No solution
Step by step:
10x-2(5x+2)=12
10x-10x-4=12
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4 0
3 years ago
How would you answer this question? thanks
Bogdan [553]

Answer:

What is the question so we can answer

6 0
2 years ago
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
Please help with Math :) Thanks!
algol [13]

Last choice the area becomes 25 times greater

6 0
3 years ago
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