420 miles in 7 hours

Simplify. 8^-4 8-^10 thats a fraction to A) 8^-14 B) 8^-6 C) 8^6 D) 8^14

gogolik [260]

We have 8^(-4) over 8^(-10). The bases are both 8, so we subtract the exponents (numerator minus denominator).

$\frac{8^{-4}}{8^{-10}} = 8^{-4-(-10)} = 8^{-4+10} = 8^{6}$

The final answer is choice C) 8^6

5 0

4 years ago

What properties does a square have in common with a quadrilateral?

satela [25.4K]

B and C are the only correct answers

4 0

3 years ago

I NEED HELP PLS I WILL GIVE CROWN: Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of

katrin2010 [14]

Answer:

Mr. Crow dimension of the lawn = 85 × 40

Area of the lawn = 3250 square feet

Step-by-step explanation:

Let x represents the width of the rectangle,

Then According to the question,

The length of the rectangle = 2 x + 5

Also it is given that the perimeter of the rectangle = 250 feet.

But we know that the perimeter of the rectangle = 2 × ( length + width)

Thus, the perimeter of the rectangle = 2( 2x+5+x) = 2(3x+5) = 6x+10

If x = 30, the perimeter of the rectangle = 6 × 30 + 10 = 190 < 250

Thus, x ≠ 10.

If x = 50, the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x = 40, the the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40 = 3250 square feet.Let x represents the width of the rectangle,

Then According to the question,

The length of the rectangle = 2 x + 5

Also it is given that the perimeter of the rectangle = 250 feet.

But we know that the perimeter of the rectangle = 2 × ( length + width)

Thus, the perimeter of the rectangle = 2( 2x+5+x) = 2(3x+5) = 6x+10

If x = 30, the perimeter of the rectangle = 6 × 30 + 10 = 190 < 250

Thus, x ≠ 10.

If x = 50, the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x = 40, the the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40 = 3250 square feet.

8 0

3 years ago

Kathy is measuring the rainfall in a rain gauge for her science project. The first week, she measured 21/4 inches of rain. The s

Genrish500 [490]

Answer:

Rain gauges are thought to be the most ancient weather instruments, and they're believed to have been used in India more than 2,000 years ago. A rain gauge is really just a cylinder that catches rain. If an inch collects in the cylinder, it means an inch of rain has fallen. It's that simple. Most standard rain gauges have a wide funnel leading into the cylinder and are calibrated so that one-tenth of an inch of rain measures one inch when it collects inside. The funnel is 10 times the cross-sectional area of the tube. Rainfall as low as .01 inches can be measured with this instrument. Anything under .01 inches is considered a trace. This standard rain gauge is shown in the following figure.

Rain gaugerainfall measurements.

Rain gauge—rainfall measurements.

Weather-Speak

A rain gauge is an instrument that measures the amount of rainfall at a given time interval.

In the more modern era, a common rain gauge is called the tipping bucket type. A bucket doesn't really tip—a pair of small receiving funnels alternate in the collection of the rain. When one fills up with water, it tips and spills out, and the other comes into place to do the collecting. These little funnels tip each time rainfall amounts to .01 inches. The tip triggers a signal that is transmitted and recorded.

Of course, these rain gauges have a problem when the temperature drops below freezing, so the standard versions are heated for the occasion.

What about snowfall? When snow falls on these heated rain gauges, it melts, and a water equivalent is determined. The recorded precipitation is always expressed in terms of rainfall or melted snow. The snow depth doesn't count—unless, of course, you have to shovel it! Sometimes a foot of snow amounts to just a half-inch of water, other times it amounts to three inches of water. It really depends on the water equivalent of the snow, which varies widely.

On the average, 10 inches of snow is equivalent to one inch of rain, but that's only an average. If a rain gauge measures one inch of water during a snowstorm, an observer can't automatically assume that 10 inches of snow has fallen. The snow depth can only be determined the old-fashioned way—by measuring it.

That depth is determined by taking an average of three or more representative spots. A ruler is stuck into the snow, and its depth is recorded. Because of blowing and drifting, the determination of three or more representative locations is not always easy. You would think that there would be a better way, but there really isn't.

Most recently, Doppler radar has been used to estimate rainfall. We'll take a look at this newest technology in the next section.

Step-by-step explanation:

4 0

4 years ago

1. A line segment on a number line has its endpoonts at -9 and 6. Find the coordinate of the midpoint of the segment.

Salsk061 [2.6K]

1- 1.5 2-(3,1) 3- 2.2 4- 165

3 0

3 years ago

Read 2 more answers