Answer:
the correct answer in ''B''
Step-by-step explanation:
Answer:
88
Step-by-step explanation:
33 plus 55
Omg i need help on tht too
Answer:
Find the answers below
Step-by-step explanation:
Using m<X as the reference angle
Opposite YZ = 7
Adjacent XY = 10
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinX = opp/hyp
sinX =YZ/XZ
sinX = 7/√149
For cos X
cos X = adj/hyp
cos X =10/√149
Using m<Z as reference angle;
Opposite XY = 10
Adjacent YZ = 7
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinZ = opp/hyp
sinZ =10/√149
sinZ = 7/√149
For cos Z
cosZ = 7/√149
Answer:
(-∞, -1]
Step-by-step explanation:
−x−6≥−5
-x≥1
x≤-1
−2x−5>4
-2x>9
x<-9/2
So x < -9/2 V x ≤ -1
