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Rom4ik [11]
3 years ago
10

I need help with a quick question. Its posted below!

Mathematics
1 answer:
Art [367]3 years ago
4 0
Home price is $245,000. There is no down payment mentioned. 
I understand 20/4 as amortized over 20 years and balloon payment after 4 years.

Total cost would be =  Balloon payment + Total monthly payment 

4 years x 12 months = 48 months
Balloon payment =       216,789.79 x 1 mo =   216,789.79
Total monthly payment = 1,727.11 x 47 mos =  81,174.17

Total cost = 216,789.79 + 81,174.17 = 297,963.96
You might be interested in
Quality control is an important issue at ACME Company which manufacturers light bulbs. In order to conduct testing of the life h
mrs_skeptik [129]

Answer: 3424.28

Step-by-step explanation:

Given data : 378, 361, 350, 375, 200, 391, 375, 368,  321

Number of data values = 9

Mean :\overline{x}=\dfrac{\sum^n_{i=1} x_i}{n}

\\\\=\dfrac{378+361+350+375+200+391+375+368+321}{9}\\\\=\dfrac{3119}{9}\approx346.56

Variance = \dfrac{\sum^n_{i=1} (x_i-\overline{x})^2}{n-1}

\sum^n_{i=1} (x_i-\overline{x})^2 = (31.44)^2+(14.44)^2+(3.44)^2+(28.44)^2+(-146.56)^2+(44.44)^2+(28.44)^2+(21.44)^2+(-25.56)^2\\\\=27394.2224

Variance = \dfrac{27394.2224}{8}=3424.2775\approx3424.28

4 0
3 years ago
What’s the missing factors for these questions?
dem82 [27]

The answer to your question is 57.6

6 0
3 years ago
A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of
Eva8 [605]

Answer:

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=250000 represent the sample mean  

s=37500 represent the standard deviation for the sample

n=5 sample size  

\mu_o =210250 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210250  

Alternative hypothesis:\mu > 210250  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

Conclusion

Since is a one right tailed test the p value would be:  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

6 0
3 years ago
The original price of a scarf was 16$. During a store closing, a shopper saved $12 on the scarf. What percentage discount did sh
Rudiy27

Answer:

75%

Step-by-step explanation:

hope this helps!! please mark brainliest

6 0
2 years ago
I HATE PROBABILITY i never got the hang of it the question is 'if the probability of rain is 0.63 what is the probability of no
kirill115 [55]

The answer would be .37, or 37%. 100 - 63 = 37.

3 0
3 years ago
Read 2 more answers
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