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3 years ago

The audio-visual technician for a hotel ordered 4 boxes of microphone cords. There are 12 cords in each box.

2 answers:

4 0

Your equation to solve is 108-(12×4).
This is 108-48 which is 60.
There were 60 cords at the hotel before the order. Since you need to find the boxes you do 60/12 which is 5.
There were 5 boxes.

Pavel [41]3 years ago

4 0

Answer: 5 boxes.

Step-by-step explanation:

Given : The audio-visual technician for a hotel ordered 4 boxes of microphone cords.

There are 12 cords in each box.

Then, the number of cords in 4 boxes will be $4\times12=48$

If there are now a total of 108 cords at the hotel, then the number of corfds were before the order : 108-48=60

Then, the number of boxes were in hotel before the order :-

$=\dfrac{60}{12}=5$

Hence, there were 5 boxes of cords in the hotel before the order.

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Which expression represents the volume of the pyramid? One-fifth(5.2)h cm3 StartFraction 1 Over 5 h EndFraction(5.2)h cm3 One-th

anyanavicka [17]

Answer:

1/3(5.2)h cm³

Step-by-step explanation:

A solid right pyramid has a regular hexagonal base with an area of 5.2 cm2 and a height of h cm. Which expression represents the volume of the pyramid?

One-fifth(5.2)h cm3 StartFraction 1 Over 5 h EndFraction(5.2)h cm3

One-third(5.2)h cm3 StartFraction 1 Over 3 h EndFraction(5.2)h cm3

Volume of the pyramid = 1/3 × area × height

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2 years ago

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2.43 x 10^2

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3 years ago

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If i=√-1 , what is i^2 equal to ?

Alja [10]

Answer:

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3 years ago

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

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3 years ago

A film student wants to capture a shot of a satellite dish placed at the top of a building. The line of sight between the ground

ICE Princess25 [194]

The ground, the building and the line of sight between the ground camera and the top of the building form right triangle with hypotenuse equal to 45 feet and angle adjacent to this hypotenuse and ground - 50°. The building is an opposite leg to the given angle, then you should write sine function:

$\sin 50^{\circ}=\dfrac{height}{45} \\ \\ 0.766=\dfrac{height}{45}\\ \\ height=45\cdot 0.766=34.47$ .

The answer to the nearest tenth of a foot is 34.5 feet

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3 years ago