To double the principle the formula is
2p=p e^rt
2=e^rt
2=e^0.12t
Solve for t
T=(log(2)÷log(e))÷0.12
T=5.78 years
Answer:
. We assume, that the number 260 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 260 is 100%, so we can write it down as 260=100%.
4. We know, that x is 6.75% of the output value, so we can write it down as x=6.75%.
5. Now we have two simple equations:
1) 260=100%
2) x=6.75%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
260/x=100%/6.75%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 6.75% of 260
260/x=100/6.75
(260/x)*x=(100/6.75)*x - we multiply both sides of the equation by x
260=14.814814814815*x - we divide both sides of the equation by (14.814814814815) to get x
260/14.814814814815=x
17.55=x
x=17.55
now we have:
6.75% of 260=17.55
Step-by-step explanation:
Answer:
1- 4x -7 =29, x= 9
2-x/3 - 8 = 12, x=60
Step-by-step explanation:
4x-7 =29
4x= 29 +7
4x= 36
x= 9
x/3 -8 =12
x/3 = 12+ 8
x/3 = 20
x= 20(3)
x= 60
1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.
3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75
4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)
5. Since the interval include 63, it is reasonable.
