Answers:Part A: The value of x is 0.Part B: X can be any real number.
In Part A, you have to first evaluate 7^2. This is 49. Now, write the equation 49^x = 1. We know that if you raise any number to 0, then the answer is 1.
In Part B, you have to first evaluate 7^0, that is 1. Now, we have the equation 1^x = 1. In this case, 1 raised to any exponent is still only 1. Imagine 1^17, this would be 1 times itself 17 times or just 1.
Therefore any number will work in Part B.
First you can change 3 to 10/10 so that they can have the same denominator. Now, since you do that the number is now 2.
Now, do 10/10-1/10=9/10.
After do 2-4=-2.
So, your final answer is -2 9/10.
Answer:
36,000 possible codes.
Step-by-step explanation:
I guess you want the total number of arrangements possible.
The first digit can be any number from 0 to 8. the middle numbers must each be any number from 0 to 9 and the last digit must be 2,4,6 or 8.
So the number of arrangements possible = 9 * 10 * 10 * 10 * 4
= 36,000.
<h2>Multiply 50 * 14 =700 so the answer is <em><u>700</u></em></h2><h2><em>Hope this helps!</em></h2>
