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soldi70 [24.7K]
3 years ago
5

Is y=4 a function, a relation, or is it both?

Mathematics
1 answer:
Maurinko [17]3 years ago
3 0

Answer:

Function

Step-by-step explanation:

The reason it is a function is because its saying y=x. Then you just plug in the number(s) to get the function y=4.PLEASE MARK BRAINLIEST thank you!!!!!!!!!

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Changing 25/4 fraction into a mixed fraction
Veronika [31]
Divide 25 by 4 and you get 6 with a remainder of 1. That remainder of 1 can go over 4 to create the final answer of 6 and 1/4. 
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Find the value of two numbers if their sum is 12 and their difference is 4
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X + y = 12
x - y = 4
-----------------add
2x = 16
x = 8

x - y = 4
8 - y = 4
y = 4

answer
two numbers: 8 and 4

doule check
sum = 8 + 4 = 12
difference = 8 - 4 = 4
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Elena works at least 4 hours but not more than 8 hours. The amount of money Elena earns for working t hours is represented by a
mezya [45]
That makes no sense what are we supposed to figure out
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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7Dx%20-%208%3D%5Cfrac%7B1%7D%7B3%7D%283x-15%29" id="TexFormula1" title="\fr
tresset_1 [31]

Answer:

x= -18

Step-by-step explanation:

Solve for  

x

by simplifying both sides of the equation, then isolating the variable.

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3 years ago
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PLEASE HELP FAST!! I MIGHT GIVE BRAINLIEST TO FASTEST AND ACCURATE
goldenfox [79]

Answer:

1/6

Step-by-step explanation:

We want to find how long it takes for the bacteria to lose half its size. We can do this by taking one point of the bacteria and finding how long it takes to go to half its size. When t=0, 9300 * (1/64)^t = 9300 * 1 = 9300 as anything to the power of 0 is 1. Therefore, we can solve for t when the end result of the bacteria is 9300/2= 4650, making our equation

4650 = 9300 * (1/64)^t

divide both sides by 9300

1/2 = (1/64)^t

First, we can tell that 2^6 = 64*. Because of this, we can say that (1/2)^6 = 1^6/2^6 = 1/64, so (1/64)^(1/6) = 1/2. We know this because

(1/2)^6 = 64

take the 6th root of both sides

(1/2) = (64)^(1/6)

. This means that t=1/6, so the bacterial culture loses 1/2 of its size every 1/6 seconds

* if this is harder to figure out, e.g. 3 and 729, we can plug (log₃729) into a calculator

3 0
3 years ago
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