For a probability distribution the expected value is the summation of product of probabilities with their respective data values. Let x be the probability that Jackson goes gym for 2 days and y be the probability that he goes gym for 3 days.
For the given case we have following values and their probabilities:
0 : 0.1
2 : x
3 : y
So the expected value will be = 0(0.1) + 2(x) + 3(y)
Expected value is given to be 2.05. So we can write the equation as:
2x + 3y = 2.05 (Equation 1)
Also for a probability distribution, the sum of probabilities must always equal to 1. So we can set up the second equation as:
0.1 + x + y = 1
x + y = 0.9 (Equation 2)
From Equation 2 we can write the value of x to be x = 0.9 - y. Using this value in equation 1, we get:
2(0.9 - y) + 3y = 2.05
1.8 - 2y + 3y = 2.05
1.8 + y = 2.05
y = 0.25
Using the value of y in equation 2 we get value of x to be 0.65
Therefore we can conclude that:
The probability that Jackson goes to gym for 2 days is 0.65 and the probability that he goes to gym for 3 days is 0.25
Answer:
what grade?
Step-by-step explanation:
Every year he pay like 100$
Compounded gon to be half
Quarter 1.3%
Answer:
A x ≤ 17/2
Step-by-step explanation:
(2x+7) /-4 ≥ -6
Multiply each side by -4, remembering to flip the inequality
(2x+7) /-4 *-4 ≤ -6*-4
2x+7 ≤ 24
Subtract 7 from each side
2x+7-7 ≤ 24-7
2x ≤ 17
Divide each side by 2
2x/2 ≤ 17/2
x ≤ 17/2
