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3 years ago

Which is bigger four liters or one gallon

1 answer:

3 0

4 quarts=1 gallon
1 liter is slightly bigger than 1 quart

so
1L>1qt
times 4 both sides
4L>4qt=1gal
4L>1gal

4 liters is bigger

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Which representation does not show a proportional relationship between x and y?

nasty-shy [4]

Answer:

Table A

Step-by-step explanation:

looking at the two tables, we have the observations as follows;

For table B, if we divide x by y; we have a ratio of 2/3

This happens throughout the table

What this means is that x = 2/3 * y

But for table A, we notice a pattern for the first two lines

The pattern here is that x = 2y

But as we move to the next two rows, we notice this fails and thus, we fail to establish a pattern that works for all the rows;

Hence table B has a pattern for all its rows

6 0

3 years ago

Find the values of the variables

Jlenok [28]

Answer:

You can use Pythagoras theorem to calculate x:

12² + 14² = x²

144 + 196 = x²

x² = 340

x = √340 ≈ 18,44

6 0

3 years ago

An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object

Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

$1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2 + \frac{1}{2} at^2\\3) v = v_0 + at$

What do we already know?

$v_0 = 29.4 ms^-1$
The launch is straight up
$a = -9.81 ms^-2$ this is the gravitational acceleration $g$

$s_0 = 0 m$ , since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, $v = 0 ms^-2$

$v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m$

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

$s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2$

this is the equation of the whole trajectory that object makes.

and if you solve this by making $s = 0$ , you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0

3 years ago

Which line from L, M and N is the line of best fit for this scatter plot?

docker41 [41]

Answer:

it would be line M. because there is more dots around the line than compared to the 9thwr lines so m would be the best choice.

4 0

3 years ago

The diagram shows one way to develop the formula for the area of a circle. Pieces of a circle with radius r are rearranged to cr

IRINA_888 [86]

Answer:

A = 1/2(2πr)(r)

Explanation:

The circumference of the circle, 2πr, is the measure completely around the circle. When the pieces of the circle are rearranged, half of this circumference will be on the top of the parallelogram and half will be on the bottom. This means the base will be 1/2(2πr).

The approximate height of the parallelogram is the radius of the circle; this makes the area

A = 1/2(2πr)(r)

7 0

3 years ago

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