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sergey [27]
3 years ago
5

So im learning fractions and i need help, what is equal to 12/10 btw this is math.

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

Fraction Decimal Percentage

14/10 1.4 140%

13/10 1.3 130%

12/10 1.2 120%

11/10 1.1 110%

Step-by-step explanation:

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Sauron [17]
40 divide by 17 is 2.35
5 0
3 years ago
Algebra question(s), please help!!!!
Angelina_Jolie [31]

Answer:

For part A

10.08x=y

Step-by-step explanation:

252/25=10.08

x=number of hours=25

y=how much earned=252

10.08(25)=252

3 0
4 years ago
raw and label a model to find the value of 3··81 4·· 8. Then write and solve an equation that matches the model.
bagirrra123 [75]

For is mathematically given as

<h3>What is the solution of an equation that matches the model.?</h3>

Considering line segments from (0,0,0)origin to (3,0,0) , (3,5,1) and (0,5,1) under the infulence of force

Generally,  the equation for force is mathematically given as

F = z2i + 5xyj + 2y2k

Therefore, Considering u*v

u * v = (u_1j+u_2j+u_3k) * (v_1i+v_2j+v_3k)

u* v = u_1v_1(i * i) + u_1v_2(i * j)+u_1v_3(i * k) + u_2v_1(j * i) + u_2v_2(j * j)+u_2_3(j* k) + u_3v_1(k * i) + u_3v_2(k * j)+u_3v_3(k * k)

Where

i * i = j *j=k * k=0

Hence

u* v = u_1v_2k-u_1v_3j-u_2v_1k+u_2v_3i +u_3v_1j - u_3v_2i

u = (u_1,u_2,u_3) = (0,5,1)\\\\v = (v_1,v_2,v_3) = (-3,0,0)

The normal equation formed

-3y + 15z = 0

z= (1/5)y

Considering the level surface and differential surface area

h(x,y,z) = -y + 5z =0

dS = |grad(h)| dA

In terms of the x and y coordinates of (3,0,0) and (3,5,1) and (0,5,1), we can state that the ranges are 0 to 3 and 5 respectively.

In conclusion,

Read more about

#SPJ1

6 0
2 years ago
A box contains 3 green counters, 5 red counters and 6 yellow counters. A counter is selected at random. Find the probability tha
Elina [12.6K]

Answer:

6/14

Step-by-step explanation:

In total there are 14 counters. And 6 of them are yellow so the probability is 6/14 (it can also be 3/7 when simplified)

6 0
3 years ago
Using the digits 1 to 9, at most one time each, fill in the blanks to make two different pairs of two-digit numbers that have a
agasfer [191]
Do you mean no repeating numbers within the two sets? Because if so, I don't think it's possible.

I started by trying to figure out what the numbers in the tenths place should be. I used subtraction: 71 - ___ = ____. If you try it out, you can't subtract anything with a 6, 7, 8, or 9 in the tenths place because it will leave you with 11 (a repeating digit number), 10 (has a 0), or less (1-digit numbers). Also, a 3 cannot go into the tenths place because when you do 71 - 3_ , your answer will always begin with a 3 (problem because the 3 repeats), or it will contain a 0. 

Therefore, the numbers left for the tenths place are: 1, 2, 4, and 5. 1 and 5 pair up, leaving 4 and 2.
71 - 5_ = 1_   and 71 - 4_ = 2_.

Then, I tried to figure out what numbers go in the ones place. That lead me to realize they act in pairs. The pairs possible in the ones place are 2 and 9, 3 and 8, 4 and 7, 5 and 6. These numbers always go together to result with the final "1" in the "71". Using this information, I looked at the numbers I already used: 1, 2, 4, and 5. Now, looking at the pairs, I eliminated the pairs containing a number already used. This leaves me with only one pair: 3 and 8. Obviously, you need two more pairs to solve the problem, which leads me to my point of saying: This problem is impossible to solve.

I really hope someone can prove me wrong! But this is the solution I have reached for now. :)
4 0
3 years ago
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