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2 years ago

Name a coordinate point located in quadrant 4

Mathematics

2 answers:

Akimi4 [234]2 years ago

7 0

(2, -2). The quadrants are numbered for every graph. Hope that's helpful.

sergiy2304 [10]2 years ago

3 0

A point in quadrant 4 could be (-4,-2)<span />

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HELP PLEASE

frozen [14]

Answer:

it would take seven and a half hours

Step-by-step explanation:

450 ÷60 =7.5

8 0

3 years ago

3 2<br> - x. - =<br> 10 3<br> Solve and simplify

Grace [21]

6......................................... i mean this is probably wrong but yeah

8 0

2 years ago

It’s kinda urgent lol

ladessa [460]

Answer:

60m²

Step-by-step explanation:

my dude you need to know this. A=bh. A=10(6).

7 0

2 years ago

The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian

Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

$x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }$

Then the area of isosceles right triangle will be: $A=\frac{1}{2} x^2$

Therefore the area is: $A=\frac{169}{4}$

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

$S=\frac{a}{1-r}$

Substitute $a=\frac{169}{4} \ and\ r=\frac{1}{4}$ in above formula.

$S=\frac{\frac{169}{4}}{1-\frac{1}{4}}$

$S=\frac{\frac{169}{4}}{\frac{3}{4}}$

$S=\frac{169}{3}$

Hence, the Sum of the areas of theses triangles is 169/3.

7 0

2 years ago

Phillip rides his scooter to school in 6 2/5 minutes. It takes Joey 4 1/2 times as long to get to school. How long does it take

jolli1 [7]

Philip rides to school in 6 2/5 minutes.....it takes Joey 4 1/2 times as long...

4 1/2 * 6 2/5 =
9/2 * 32/5 =
144/5 =
28 4/5 minutes <== Joey's time to get to school

5 0

2 years ago