With the first problem: You always divide from the left, then the rigth. 2+246/6 = 246/6=41 41+2=43
Answer:
the probability that the shipment is accepted is 0.8865
Step-by-step explanation:
Given the data in the question;
N = 86, n/d = 5 and n = 2
now, without replacement
the probability that the shipment is accepted will be;
probability that the shipment is accepted = probability that non is defectives
so p( non is defective ) = ( (86-5)/86) × ((86-5-1)/(86-1))
p( non is defective ) = ( 81 / 86) × (80/85)
p( non is defective ) = 0.8865
Therefore, the probability that the shipment is accepted is 0.8865
5.50 x 3.87 equals 21.285. 21.285 rounded to the nearest cent is $21 dollars and 3 cents.
Answer:
1) Consider that he makes $1189 every two weeks engaged with work
2) An estimate of the opportunity cost of going on the fishing trip is $1450 in two weeks
3). If he decides to buy the truck, he has to work for about 7 weeks before going on the fishing trip
Step-by-step explanation:
From the given data
Total revenue from lawn mowing per year = 35 × 4× 5×20 = $1400
Similarly total operating costs = $2110
Total profit per annum = $11890
However total revenue per every 2 weeks = $1189
To buy the truck, sell his and go on the fishing trip it will cost = 5200-1500+250 =$3950 hence he has to work for about 6.64 or approximately 7 weeks before going on the fishing trip
2) Opportunity cost will factor in the cost of having someone work for him while away
The cost is = $250 + $120/day
Hence in two weeks it will cost him $1450
3) He has to work for about 7 weeks to be able to afford the truck
