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erica [24]
3 years ago
6

Describe how the presence of possible outliers might be identified on the following. (a) histograms gap between the first bar an

d the rest of bars or between the last bar and the rest of bars large group of bars to the left or right of a gap higher center bar than surrounding bars gap around the center of the histogram higher far left or right bar than surrounding bars (b) dotplots large gap around the center of the data large gap between data on the far left side or the far right side and the rest of the data large groups of data to the left or right of a gap large group of data in the center of the dotplot large group of data on the left or right of the dotplot (c) stem-and-leaf displays several empty stems in the center of the stem-and-leaf display large group of data in stems on one of the far sides of the stem-and-leaf display large group of data near a gap several empty stems after stem including the lowest values or before stem including the highest values large group of data in the center stems (d) box-and-whisker plots data within the fences placed at Q1 â’ 1.5(IQR) and at Q3 + 1.5(IQR) data beyond the fences placed at Q1 â’ 2(IQR) and at Q3 + 2(IQR) data within the fences placed at Q1 â’ 2(IQR) and at Q3 + 2(IQR) data beyond the fences placed at Q1 â’ 1.5(IQR) and at Q3 + 1.5(IQR) data beyond the fences placed at Q1 â’ 1(IQR) and at Q3 + 1(IQR)
Mathematics
2 answers:
Vesna [10]3 years ago
5 0

Answer:

it is D

Step-by-step explanation:

castortr0y [4]3 years ago
3 0

Answer:

Option d

Step-by-step explanation:

(d) box-and-whisker plots data within the fences placed at Q1 â’ 1.5(IQR) and at Q3 + 1.5(IQR) data beyond the fences placed at Q1 â’ 2(IQR) and at Q3 + 2(IQR) data within the fences placed at Q1 â’ 2(IQR) and at Q3 + 2(IQR) data beyond the fences placed at Q1 â’ 1.5(IQR) and at Q3 + 1.5(IQR) data beyond the fences placed at Q1 â’ 1(IQR) and at Q3 + 1(IQR)

Outliers are defined as points or readings which lie far away from the normal readings.  Extreme items such as very large or very large compared to the other values are outliers.

OUtliers are caused by sampling errors, or variability. Outliers give misleading results sometimes very seriously

Hence all entries are arranged in ascending order , middle entry marked as median, and 1/4 th after is marked as I quartile Q1, and 3/4th is marked as Q3

Outliers are found out by fixing the range for non outliers as

(Q1-1.5IQR,Q3+1.5IQR) where IQR = Q3-Q1

The values beyond this intervals are outliers

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What is the effective interest rate on an account that earns 5.5% compounded monthly?
nataly862011 [7]

Answer:

.46%

Step-by-step explanation:

.055/12= .00458= .46%

4 0
3 years ago
Triangles ABC and EDC are outlined on a bridge. The triangles share vertex C and angles D and B are right angles. A new bridge s
dexar [7]

CHECK THE ATTACHED FIQURE FOR THE BRIDGE

Answer:

60 ft

Step-by-step explanation:

From the question we know that triangles ABC and EDC are in a 1:1 with this given ratio it implies that

triangles ABC and EDC are congruent then we can say

side EC = side AC

3x + 9 = 5x - 5

Then we can simplify to know value of x

3x + 14= 5x

2x = 14

x = 7

But we know that AC= 5x - 5 , then substitute value of x into it

AC = 5x + 5 = 5(7) - 5

= 35 - 5

AC= 30 ft

Also EC= 3x + 9 then substitute value of x into it

EC = 3x + 9 = 3(7) + 9

= 21 + 9

EC= 30 ft

Then the the distance between the top and bottom of the bridge, in feet, = EC+AC

= 30 + 30 = 60 ft

4 0
3 years ago
Round 2.51 to 1 decimal place
Leni [432]

Answer:

2.5

Step-by-step explanation:

It's because 1is less than 5

8 0
2 years ago
Read 2 more answers
Х Y
Montano1993 [528]

Answer:

y = 0.5x + 3

Step-by-step explanation:

7 0
2 years ago
What is the equation of the line of the best fit for the following data? Round to the slope and y-intercept of the line to three
BigorU [14]

Answer:

D. y=-0.927x+13.634

Step-by-step explanation:

We graph the points on the graph. The graph is attached.

Let us take two points (1, 14) and (15, 1), and calculate the slope mbetween them <em>(we choose these points because the line passing through them will be the best fit for all points) </em>

m=\frac{14-1}{1-15} =\frac{13}{-14} =-0.9286

Thus we have the equation

y=-0.9286x+b

Let us now calculate b from the point (1,14)

14=-0.9286(1)+b

b=14.9286

So the equation we get is

y=-0.9286x+14.9286

Let us now turn to the choices given and see which choice is closest to our equation: we see that choice D. y=-0.927x+13.634 is the closest one, so we pick it.

4 0
3 years ago
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