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Annette [7]
3 years ago
9

Which of the following are true statements about the expression 12^5

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
12×12×12×12×12 is equivalent to 12^5 (a^b means a is to be written down B times all being multiplied.)
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HELP ME PLZZZZZ Now class test
Airida [17]

Answer: 0.59 cents per a pounds =y

Step-by-step explanation:I dont know if this is what you are talking about

7 0
3 years ago
General term for -13, -11, -9, -7
timurjin [86]

The general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

<h3>Arithmetic progression</h3>

-13, -11, -9, -7

  • First term, a = -13
  • Second term = -11

Common difference, d = Second term - first term

= -11 - (-13)

= -11 + 13

= 2

Therefore,

Tn = a + (n - 1)d

Where,

  • n = number of terms

Tn = a + (n - 1)d

= -13 + (n - 1)2

= -13 - 2n - 2

Tn = -15 - 2n

So therefore, the general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

Learn more about arithmetic progression:

brainly.com/question/6561461

#SPJ1

5 0
2 years ago
Use the diagram to find the measure of arc. AB and CD and the diameters of the circle F
dybincka [34]

Answer:

11). m(\widehat{DE}) = 90°

12). m(\widehat{AEC}) = 212°  

Step-by-step explanation:

A circle F with AB and CD are the diameters has been given in the figure attached.

11). Since, m(\widehat{AB}) = 180°

    and m(\widehat{AB})=m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE})

    Therefore, m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE}) = 180°

    32° + m(\widehat{DE}) + 58° = 180°

    m(\widehat{DE}) = 180° - 90°

                = 90°

12. Since, m(\widehat{AD})=m(\widehat{BC}) = 32°

                 m(\widehat{AEC}) = m(\widehat{AB})+m(\widehat{BC})

                                = 180° + 32°

                                = 212°

7 0
3 years ago
Solve 5x^2 - 7x + 2 = 0 by completing the square.
Reika [66]

Answer:  The correct option is (c) \dfrac{49}{100}.

Step-by-step explanation:  We are given to solve the following quadratic equation by the method of completing the square:

5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.

So,

x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.

Thus, the required solution is x=1,~-\dfrac{2}{5}. and the value of the constant added is \dfrac{49}{100}.

Option (c) is correct.

3 0
3 years ago
What is the probability that the value the standard normal random variable assumes will be greater than 0.64?
neonofarm [45]
For the answer to the question above, I'll provide a computation on my answer to give clarity and understanding to my answer.
<span>P(z> 0.64) = 1- P(z<0.64) </span>
<span>P(z<0.64) = .73891 </span>
<span>P(z> 0.64) = 1- 0.73891 =
So the answer to your question is
0.26109 

I hope my answer helped you. Have a nice day!</span>
5 0
3 years ago
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