How do you find the surface area (total area)

Two airplanes leave the airport. Plane A departs at a 42° angle from the runway, and plane B departs at a 44° angle from the run

rewona [7]

Answer:

2nd choice

Step-by-step explanation:

Horizontal distance = x

angle = α,

tanα = 15/x, so x = 15/tanα

For A, α = 42°, x = 15/tan42° = 16.66 miles

For B, α = 44°, x = 15/tan44° = 15.53 miles

so the answer is 2nd choice

6 0

2 years ago

A large automobile insurance company selected samples of single and married male policyholders and recorded the number who made

Ipatiy [6.2K]

Answer:

Step-by-step explanation:

Given the following :

Single policy holders (n1) = 900

Number making claims (x1) = 135

Married Policy holders (n2) = 400

Number making claims (x2) = 24

α = 0.05

a. Use a level of significance α = 0.05. Test to determine whether the claim rates differ between single and married male policyholders. Explain your determination.

Null: p1 - p2 = 0

Alternative : p1 - p2 ≠ 0

p = (n1p1 + n2p2) / n1 + n2 ;

p1 = x1/n1 = 135 / 900 = 0.15

p2 = x2/n2 = 24 / 400 = 0.06

p = (900*0.15 + 400*0.06) / (900 + 400)

p = 0.1223076

Test statistic (z):

(p1 - p2) / √p(1-p)(1/n1 + 1/n2)

(0.15 - 0.06) / √0.12231(1-0.12231)(1/900 + 1/400)

= 4.5710979

Decision:

Reject Null if P < α

Obtaining p value from z score using calculator :

P value = 0.0001

0.0001 < 0.05

Hence,

Reject Null

8 0

4 years ago

What is the walue of (6561)^0.25

vodomira [7]

Equivalent ways of stating this expression are
$(6561)^{0.25}=6561^{ \frac{1}{4} }= \sqrt[4]{6561}$
I used a calculator to simplify and got 9.
This is true because $9^4=6561$ .

5 0

4 years ago

If you rent a car, you can (1) return it with a full gas tank, (2) return it without filling it and pay $3.45/gallon or (3) acce

kobusy [5.1K]

Answer:

a) return it with a full gas tank

b) return it with a full gas tank

c) accept a fixed price

d) answers do not change

Step-by-step explanation:

considering the 3 scenarios under the assumption that the car initially has the tank full , then:

1) return it with a full gas tank : cost=$3.15 /gallon / (28 miles/gallon)* number of miles

2) return it without filling it: cost= $3.45 /gallon / (28 miles/gallon) * number of miles

3) accept a fixed price: $35

then option 1 is always better than option 2. The option 1 is better than the third when

$3.15 /gallon / (28 miles/gallon)* number of miles < $35

number of miles < 35/3.15*28 = 311 miles

then the choice for

a) return it with a full gas tank

b) return it with a full gas tank

c) accept a fixed price

for d) , assuming the best case scenario that the filling station is on the main pathway so you do not have to deviate to reach the station, then the cost for option 1 is altered

1) return it with a full gas tank : cost= cost of filling the tank + cost for the stops at the filling station

cost=$3.15 /gallon / (28 miles/gallon)* number of miles + $12/(hour*stop) * 15 min* 1 hour/60 min * 1 stop/20 gallons / (28 miles/gallon) * number of miles = $ 0.1178 /mile * number of miles

while option 2) remains the same : $0.1232/mile*number of miles

then option 1 is still better than option 2. The option 1 is better than the third when

$ 0.1178 /mile*number of miles < $35

number of miles < 35/0.1178 = 297 miles

then the answers do not change

6 0

4 years ago

The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser

Liono4ka [1.6K]

The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

$z-score= \frac{X-Mean}{Standard Deviation}$
$z-score= \frac{405.5-402.7}{8.8} =0.32$

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

$P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)$

from the z-table, the reading $P(Z\ \textless \ 0.32)$ gives 0.6255

hence,
$P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475$

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0

3 years ago