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andrew11 [14]
2 years ago
15

Two airplanes leave the airport. Plane A departs at a 42° angle from the runway, and plane B departs at a 44° angle from the run

way. Which plane has a larger horizontal distance from the airport when its altitude is 15 miles? Round the solutions to the nearest hundredth.
Plane B because it was 20.85 miles away
Plane A because it was 16.66 miles away
Plane A because it was 20.18 miles away
Plane B because it was 15.53 miles away
Mathematics
1 answer:
rewona [7]2 years ago
6 0

Answer:

2nd choice

Step-by-step explanation:

Horizontal distance = x

angle = α,

tanα = 15/x, so x = 15/tanα

For A, α = 42°,  x = 15/tan42° = 16.66 miles

For B, α = 44°,  x = 15/tan44° = 15.53 miles

so the answer is 2nd choice

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