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nekit [7.7K]
3 years ago
6

What is the slope of the line 3y=4x+5? Answer choices: A. 5/3 B. 4/3 C. 2 D.4

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

B. 4/3

Step-by-step explanation:

slope-intercept formula is y=mx+b, where m is the slope and y has to be by itself.

dividing 4 by 3 cant be more simplified than 4/3.

Scilla [17]3 years ago
3 0

Convert this equation into slope intercept form ( y = mx + b). To do this isolate y by dividing 3 to both sides

\frac{3y = 4x + 5}{3}

y = \frac{4}{3}x + \frac{5}{3}

^^^^This is the slope intercept form for this line

m in the equation is the slope of the line. In this case the slope is B. \frac{4}{3}

Hope this helped!

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15 out of 25 perfer skittles to M&MS. what percent of students prefer skittles ​
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60%

Step-by-step explanation:

Just divide 15 by 25 and then move the decimal point 2 places to the right. Then turn that number into a percentage.

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Step-by-step explanation:

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3 years ago
Suppose a and b are independent events if p(a/b)=.25 and p(b)=.6 what is P(AnB)?
Talja [164]

Answer:

0.15

Step-by-step explanation:

<u>Independent Probabilities Formula</u>

P(A | B) = P(A) = P(A ∩ B) ÷ P(B)

P(A | B) = 0.25

P(A) = 0.25

P(B) = 0.6

If P(A) = P(A ∩ B) ÷ P(B)

P(A ∩ B) = P(A) × P(B)

P(A ∩ B) = 0.25 × 0.6

P(A ∩ B) = 0.15

4 0
3 years ago
What is the value of this expression when<br> d= 47 and f = 3?<br> 6 (d - f) +f
agasfer [191]

Answer:

267

Step-by-step explanation:

We are given the expression:  6 (d - f) +f

The value of the expression when d= 47 and f = 3 is :

6 (47 - 3) +3 = 6×(44) + 3 = 264 + 3 = 267

=267

7 0
2 years ago
Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
3 years ago
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