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3 years ago

What is the slope of the line 3y=4x+5? Answer choices: A. 5/3 B. 4/3 C. 2 D.4

Mathematics

2 answers:

yawa3891 [41]3 years ago

7 0

Answer:

B. 4/3

Step-by-step explanation:

slope-intercept formula is y=mx+b, where m is the slope and y has to be by itself.

dividing 4 by 3 cant be more simplified than 4/3.

Scilla [17]3 years ago

3 0

Convert this equation into slope intercept form ( y = mx + b). To do this isolate y by dividing 3 to both sides

$\frac{3y = 4x + 5}{3}$

y = $\frac{4}{3}x + \frac{5}{3}$

^^^^This is the slope intercept form for this line

m in the equation is the slope of the line. In this case the slope is B. $\frac{4}{3}$

Hope this helped!

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3 years ago

Suppose a and b are independent events if p(a/b)=.25 and p(b)=.6 what is P(AnB)?

Talja [164]

Answer:

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Step-by-step explanation:

<u>Independent Probabilities Formula</u>

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4 0

3 years ago

What is the value of this expression when<br> d= 47 and f = 3?<br> 6 (d - f) +f

agasfer [191]

Answer:

267

Step-by-step explanation:

We are given the expression: 6 (d - f) +f

The value of the expression when d= 47 and f = 3 is :

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2 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

3 years ago