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Fittoniya [83]
4 years ago
14

What is w for p=-aw+9

Mathematics
1 answer:
klio [65]4 years ago
6 0
The answer is w=p-9/a
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The image below represents a 12 x 16 room with an 8 x 10 piece of linoleum centered in the room . The yellow and blue rectangles
AleksAgata [21]

multiply 12 and 16 then multiply 8 and 10 then add them up to get 15,360

4 0
4 years ago
10r - 5r + 3r - 8r<br> Simplify the expression by combining like terms
LekaFEV [45]

Answer:

0

Step-by-step explanation:

10r - 5r + 3r - 8r

all of these have the common term of r, therefore simple addition of the integers would get you the answer in terms of r

10-5+3-8=0

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3 years ago
If a point P(1, –2) is reflected across the line x = 3, what are the coordinates of its reflection image?
Simora [160]
P'=(5,-2)
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3 years ago
A bicycle is on sale at a 15% discount. The sale price is $680. What was the original price?
Nostrana [21]

Answer:

$800 is the original price

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15% discount

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5 0
3 years ago
Read 2 more answers
the coordinates of the vertices of a rectangle in order are (5,2), (-1,4), (-2,1) and (4,-1). what is the perimeter of the recta
Anna [14]

Answer:

19 units

Step-by-step explanation:

Plot points  A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units

The perimeter of the rectangle ABCD is

AB+BC+CD+DA=2\sqrt{10}+\sqrt{10}+2\sqrt{10}+\sqrt{10}=6\sqrt{10}\approx 18.97\ units\approx 19\ units

3 0
3 years ago
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