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Sergio039 [100]
3 years ago
14

From least to greatest 0.44, 87/200, 43.7%, 21/50

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
21/50, 0.44, 87/200 43.7%
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Mrs. McCarthy bought 1.5 pounds of chicken from Smiths. She paid a total of $6.75 for the chicken. What was the price per pound?
REY [17]

$ 6.75/ 1.5 lbs

$4.50 per lb

4 0
2 years ago
HELP PLEASE 10 POINTS!!!!!!!!!!!
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Answer:

0.0000000642 = 6.42 \times  {10}^{ - 8}

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5 0
3 years ago
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Look at the function below.
weqwewe [10]
The answer is B because the x describes the domain and it can also be the input value
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3 years ago
3(12-3y^2) Help solve this please
HACTEHA [7]
Step 1. <span>Distribute

</span>3*12+3*-3 y^{2}
<span>
Step 2. Simplify </span>3*12 to 36

36+3*-3 y^{2}

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36-9 y^{2}

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5 0
3 years ago
A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t
sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is  11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

\text{Area of painting}=l\times b

\text{Area of painting}=24\times 11

\text{Area of painting}=264 \text{ in}^2

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

\text{Area of painting with mat}=30\times 17

\text{Area of painting with mat}=510 \text{ in}^2

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\

\text{Area of mat}=510-264

\text{Area of mat}=246 \text{ in}^2

Hence, the area of the mat is 246 in².

6 0
2 years ago
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