From least to greatest 0.44, 87/200, 43.7%, 21/50

Simplify −2i sqrt −12 please help!

defon

$\bf \textit{recall that }i^2=-1\\\\
-------------------------------\\\\
-2i\sqrt{-12}\quad 
\begin{cases}
12=2\cdot 2\cdot 3\\
\qquad 2^2\cdot 3
\end{cases}\implies -2i\sqrt{-1\cdot 2^2\cdot 3}
\\\\\\
-2i\sqrt{-1}\cdot \sqrt{2^2}\cdot \sqrt{3}\implies -2i\cdot i\cdot 2\cdot \sqrt{3}\implies -4i^2\sqrt{3}
\\\\\\
-4(-1)\sqrt{3}\implies 4\sqrt{3}$

7 0

3 years ago

Figure 22: Find the total yellow area.

Pachacha [2.7K]

Step-by-step explanation:

area of rectangle = l × h

= 9 × y

= 72

9 × y = 72

y = 72÷9

y = 8cm

area of circle = 50.27cm²

total area of the logo = 2(50.27) + 72

= 100.54 + 72

= 172.54cm²

3 0

3 years ago

A certain material decays at a rate 0.92% per year. How much of 260 grams of the material will be left in 11years ?

Dmitriy789 [7]

A= p (1-r)^t
A material after 11 years
P current amount 260
R rate of decreases 0.0092
T time 11 years

A=260×(1−0.0092)^(11)
A=234.87 round
A=235

4 0

3 years ago

Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the

Verdich [7]

Answer:

1364 is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

1. 5 digit numbers:

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

$4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024$

2. 4 digit numbers:

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

$4 \times 4 \times 4 \times 4 \\ \Rightarrow 256$

3. 3 digit numbers:

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

$4 \times 4 \times 4 \\ \Rightarrow 64$

4. 2 digit numbers:

We have 2 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

$4 \times 4 \\ \Rightarrow 16$

5. 1 digit numbers:

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

$4$

We can add all the above possibilities to find the total.

So, number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = 1364

3 0

3 years ago

How can you solve a system of two equations or inequalities in which one is linear and one is quadratic?

stealth61 [152]

Answer:

Solve the inequality as though it were an equation. The real solutions to the equation become boundary points for the solution to the inequality. Make the boundary points solid circles if the original inequality includes equality; otherwise, make the boundary points open circles.

Step-by-step explanation:

5 0

3 years ago