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scoundrel [369]
3 years ago
10

The function f is defined by f(x)=x^2-5 find f(2y)

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0
\bf f(x)=x^2-5\qquad \qquad f(2y)=(2y)^2-5\implies f(2y)(2^2y^2)-5
\\\\\\
f(2y)=4y^2-5
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I don't know how to solve this and the answer isn't 4 or 0 so what is it?4=-4+a​
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3 years ago
Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.
Dmitry [639]
Note that
\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}

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tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

Therefore
tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} =  \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )}  = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}

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svetlana [45]
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Read 2 more answers
PLEASE HELP IMAGE ATACHED
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What kind of problems or what are you trying to ask? 
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Answer:

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Step-by-step explanation:

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