Question

Find the equation of a line containing the given point and slope (10,5); m=9/20

Answer 1

$\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 10}}\quad ,&{{ 5}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{9}{20} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-5=\cfrac{9}{20}(x-10)\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-5=\cfrac{9}{20}x-\cfrac{9}{2}\implies y=\cfrac{9}{20}x-\cfrac{9}{2}+5\implies y=\cfrac{9}{2}x+\cfrac{1}{2}$