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2 years ago

What is the median of 60 57 53 78 44 51 please help and thank u

2 answers:

8 0

To find the median cancel out numbers on both sides, until one is left in the middle and if there are two in the middle add them up and divide by two.

So in this case the median is
53+78
131 / 2
65.5

Svetlanka [38]2 years ago

6 0

First put them in order....

44, 51, 53, 57, 60, 78

53 and 57 are the two middle numbers so add them together and divide by 2
your answer is 55

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Which ordered pairs make the open sentence true? 3x+y<14 Select all the correct answers. (7, −7) (−1, 6) (3, 6) (4, −1) (6, 0

Jet001 [13]

Answer:

(4, - 1)

(-1, 6)

Step-by-step explanation:

Given the expression :

3x+y<14

Test the opprions to find out the true statement.

(7, - 7)

3(7) + (-7) < 14

21 - 7 < 14

15 < 14 (not true)

(-1, 6)

3(-1) + 6 < 14

3 + 6 < 14

9 < 14 ( true)

(3, 6)

3(3) + 6 < 14

9 + 6 < 14 ( not true)

(4, - 1)

3(4) - 1 < 14

12 - 1 < 14 ( true)

(6,0)

3(6) + 0 < 14

18 < 14 ( not true)

4 0

2 years ago

A(x) = -0.015x^3+1.05xA ( x ) = − 0.015 x 3 + 1.05 x gives the alcohol level in an average person's blood x hrs after drinking 8

goldfiish [28.3K]

Answer:

Yes

Step-by-step explanation:

the function that gives the alcohol level is:

$A ( x ) = - 0.015 x^3 + 1.05 x$

where x is the number of hours.

we need to know if after 4 hours an average person is legally drunk, thus:

$x=4$

and we substitute this in the function:

$A ( 4 ) = - 0.015 (4)^ 3 + 1.05(4)$

solving these operations we obtain:

$A(4)=-0.015(64)+4.2\\A(4)=-0.96+4.2$

$A(4)=3.24$

the alcohol level after 4 hours is 3.24.

Since a person is considered to be legally drunk if the level exceeds 1.5, and we obtained 3.24 which is greater than 1.5, a person who has been drinking for 4 hours under the conditions indicated by the problem would be considered legally drunk.

5 0

2 years ago

Help give me the formula and the answer and plz explain so I also benefit:)

Fudgin [204]

I think 48 cubic cm..... (Tell me if I did it wrong or not)

4 0

3 years ago

I need help combining functions!

postnew [5]

$\bf \begin{cases}
f(x)=\cfrac{2}{x}\\\\
g(x)=\cfrac{x}{x+2}
\end{cases}\qquad g[\quad f(x)\quad ]=\cfrac{[f(x)]}{[f(x)]+2}$

$\bf (g\circ f)(x)\iff g[\quad f(x)\quad ]=\cfrac{\boxed{\frac{2}{x}}}{\boxed{\frac{2}{x}}+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{\frac{2}{x}}{\frac{2x+2}{x}}\implies g[\quad f(x)\quad ]=\cfrac{2}{x}\cdot \cfrac{x}{2x+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{2x}{2x^2+2x}\implies g[\quad f(x)\quad ]=\cfrac{2x}{2x(x+1)}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{1}{x+1}$

5 0

3 years ago

The product of a number and 16 is equal to the sum of the number and 14

nevsk [136]

Step-by-step explanation:

let number be x

16x = 14 + x

16x - x = 14

15x = 14

x = 14 ÷ 15

x = 0.9

7 0

2 years ago