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2 years ago

11

Mr.Thompson took his 5 children to the bowling alley. The cost for children 12 and older is 3.50. The cost for children under 12

is 2.25. He spends a total of 16.25. How many of his children are 12 and older?

1 answer:

WINSTONCH [101]2 years ago

4 0

4 of the five children are older than 12

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Can you please answer this question

schepotkina [342]

Answer:

1/40

219/250

69/16

Step-by-step explanation:

1.

0.025=(025)/(1000)=1/40

2.

0.876=876/1000=219/250

3.

4.3125=43125/10000=1725/400=69/16

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2 years ago

The level of college education and wages earned are known to have a strong positive association. Karen concluded that a college

vazorg [7]

Answer:

Karen's conclusion is not valid because association does not imply causation.

Step-by-step explanation:

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2 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

so

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

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2 years ago

iogann1982 [59]

Okay thanks for letting me know I love you love love bye

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2 years ago

If f(x) = x2 – 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?

Artyom0805 [142]

Answer:

The answer is second one (-2)

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2 years ago