All categories

3 years ago

Find the value of x the triangle shown below

Mathematics

2 answers:

Novay_Z [31]3 years ago

3 0

Answer:

$82$

Step-by-step explanation:

$24+74+x=180$

$98+x=180$

$x=180-98$

$x=82$

alexira [117]3 years ago

3 0

Answer:

x =82

Step-by-step explanation:

The sum of the angles in a triangle is 180 degrees

24+74+x = 180

Combine like terms

98+x = 180

Subtract 98 from each side

98+x-98= 180-98

x =82

You might be interested in

What is 572 rounded to the nearest hundred

nordsb [41]

The answer is 600. 572 rounded to the nearest hundred is 600

4 0

3 years ago

Some engines require oil to be mixed with gasoline. For every gallon of gas used, 4 ounces of oil should be added. How much gas

Soloha48 [4]

2 gallons because 4 ounces are in one gallon in gas

i think

3 0

4 years ago

Read 2 more answers

2 digit division by partial quotients 36 divided by 540

tresset_1 [31]

Divide use partial quotients 36 divided by 540. 1 ... So where looking for the quotient of 36 and 540 ... Mathematics; 5 points; 2 hours ago.
[PDF]

4 0

4 years ago

HELP PLEASE SUPER EASY

Tema [17]

Answer:

Step-by-step explanation:

because if you look at it, the rest have a number that is continuously being added where as number 2. is being multiplied by 2.. hope this helps love<3

8 0

3 years ago

the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant

Tamiku [17]

Answer:

The rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters is $24\pi \:\frac{cm^3}{s}$

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

$\frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}$
$\frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}$
The volume of a cone of radius r and height h is given by $V=\frac{1}{3} \pi r^2 h$

We want to find the rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

$\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]$

Substituting the values we know into the above formula:

$\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}$

5 0

4 years ago