Question

Please help ASAP!!!!!​

Answer 1

Answer: OPTION C

Step-by-step explanation:

Complete the square:

Having the equation in the form $ax^2+bx=c$, you need to add $(\frac{b}{2})^2$ to both sides of the equation:

You can identify that "b" in the equation $x^2+6x=5$ is:

$b=6$

Then:

$(\frac{6}{2})^2=3^2$

Add this to both sides:

$x^2+6x+3^2=5+3^2$

Rewriting, you get:

$(x+3)^2=14$

Solve for "x":

 $x+3=\±\sqrt{14}\\\\x+3=\±\sqrt{14}\\\\x=\±\sqrt{14}-3$

Then, the solutions are:

$x=-3+\sqrt{14}\ or\ x=-3-\sqrt{14}$