Answer:
Step-by-step explanation:
add the top of one and the bottom of the other then the top of the other and the bottom of one
Sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
As given,
Let a-d, a, a +d be three numbers
Sum =33
⇒a-d + a +a +d =33
⇒ a =11
Sum of cubes= 5049
⇒ (a-d)³ + a +(a +d)³ =5049
⇒ a³ -d³ -3a²d +3ad² + a³ +a³ +d³ +3a²d +3ad² =5049
⇒3a³ + 6ad² = 5049
⇒ d=± 4
Therefore, sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
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Answer:
Trapezoid
21 is the perimeter.
24 is the area.
Step-by-step explanation:
Let's do the perimeter first, 8 + 4 = 12.
Now we have to get the side lengths. We can do this by using the Pythagoras Theorem by making an imaginary line to form a right triangle. The lengths are 2 and 4. So, 4 + 16 = 20. Square root of 20 + square root of 20 = ~9
12 + 9 = 21
21 is the perimeter.
Now, let's solve the area. The a is 4, b is 8. So 4 + 8 = 12/2 = 6. The height is 4 so 6 * 4 = 24.
24 is the area.
Hope this helped ya
:)
Hi I'm new to this website so I wanted to comment that I'm having the same complication with that exact same problem
Answer:
9 or 8 .... not 10 tho
Step-by-step explanation:
5 and 10 side has more of the circle than the 4 and x side.
