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3 years ago

14

Chad will drive 672 more miles . He continues to drives at the same rate . How many hours will it take Chad to drive the 672 mil

es?

1 answer:

tekilochka [14]3 years ago

8 0

12 hours, you can use proportions, miles/hours. 56/1=672/x. x=12.

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Consider the statement “Worldwide, there are more than $2.5 trillion in credit card transactions annually.”

vlada-n [284]

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Step-by-step explanation:

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3 years ago

Find the quotient of (11 ^ 18)/(11 ^ 3)

astraxan [27]

Answer:

The first choice, $11^{15}$ .

Step-by-step explanation:

The numerator, $11^{18}$ , is equivalent to eighteen " $11$ " multiplied together:

$11^{18} = \underbrace{11 \times 11 \times 11 \times 11 \times \cdots \times 11 \times 11}_{\text{$18$ in total}}$ .

On the other hand, the denominator, $11^{3}$ , is equivalent to three " $11$ " multiplied with one another:

$11^{3} = 11 \times 11 \times 11$ .

Dividing $11^{18}$ by $11^{3}$ would eliminate three " $11$ " from the numerator:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & \frac{(11 \times 11 \times 11) \times \overbrace{11 \times \cdots \times 11}^{\text{$(18 - 3)$ in total}}}{(11 \times 11 \times 11)} \\ =\; & \overbrace{11 \times \cdots \times 11}^{\text{$15$ in total}} \\ =\; & 11^{15}\end{aligned}$ .

In general, dividing an expression by $y^{b}$ ( $y \ne 0$ ) is equivalent to multiplying that expression by $y^{-b}$ .

For example, in this question, dividing $11^{18}$ by $11^{3}$ would be equivalent to multiplying $11^{18}\!$ by $11^{-3}$ . In other words:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & 11^{18} \times 11^{-3} \\ =\; & 11^{18 - 3} \\ =\; & 11^{15}\end{aligned}$ .

6 0

2 years ago

The inequality 10.45b + 56.50 < 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceedin

PSYCHO15rus [73]

We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.

6 0

3 years ago

Read 2 more answers

What is the answer?

ella [17]

<h2><em>I believe 10.91ft but I'm not sure.</em></h2>

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3 years ago

What is the value of f(16) - f(0) when f(x) = 4x - 8?

levacccp [35]

That would be 4(16) - 8 - (4(0) - 8) = 64 - 9 - 0 + 8 = 63 Answer

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3 years ago

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