Get it in form 4P(y-k)=(x-h)^2
add 8y to both sides
x^2-6x+49=8y
complete the square
-6/3=-3, (-3)^2=9
(x^2-6x+9)+40=8y
(x-3)^2+40=8y
minus 40 both sides
(x-3)^2=8y-40
undistribute 8 on right side
(x-3)^2=(y-5)8
4P(y-k)=(x-h)^2
4(2)(y-5)=(x-3)^2
(h,k) is center
p is distance from vertex to directix and also from vertex to focus
p=2
vertex=(3,5)
in that form, the prabola opens up so
directix is 2 below vertex
focus is 2 above vertex
up and down is y so
5-2=3
5+2=7
directix is y=3
focus=(3,7)
vertex=(3,5)
It means that the value will not be included. So if the open circle coincides with 2 on the x-axis then your limit will have x<2, which also means that the function is not continuous.
The side of the square = 16 in
When a circle is inscribed in a square, the length of each side of the square is equal to the diameter of the circle.
So, the diameter of the circle is equal to 16 in => radius = 8 in
Circumference = 2πr = 2π8 = 16π = 50.24
