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Ksju [112]
3 years ago
9

Find the outlier of the set of data: 80, 71, 75, 69, 74, 17, 82 A. 82 B. 81 C. 74 D. 17

Mathematics
1 answer:
gogolik [260]3 years ago
7 0
D: 17, it is further from the mean than any other number by far.
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Requie<br> 2) 20 + (-45)
harkovskaia [24]

Answer:

20 + (-45) = -25

6 0
2 years ago
Read 2 more answers
Jimmy purchased a package of jelly beans that contained 75 jellybeans. Out of the 75 jellybeans, 8 are pink, 17 are orange, 22 a
Luba_88 [7]

Find completion to question in comment section.

Answer:

D. One of the jellybeans that slipped out was orange and one was black

Step-by-step explanation:

We calculate the option with the highest probability of occurrence :

Total number of jellybean = 75

n(T) =75

n(Pink) = 8

n(red) = 22

n(Orange) = 17

n(green) = 8

n(white) = 6

n(black) = 4

We assume that the jelly beans must have slipped out one after the other.

Evaluating the options :

A.)

P(pink) and P(white)

8/75 * 6/74 = 0.0086486

B.)

P(green) and P(green)

8/75 * 7/74 = 0.0100900

C.)

P(white) and P(white)

6/75 * 5/74 = 0.0054054

D.)

P(orange) and P(black)

17/75 * 4/74 = 0.0122522

From the probability values obtained, the highest is D. Hence, the most likely to have occurred is One of the jellybeans that slipped out was orange and one was black

5 0
2 years ago
I really don't get this type of math so can someone please help me with this thank you
solmaris [256]
The area for a trapezoid is A=1/2(b*1+b*2)h
Your base is your two parallel sides, and your parallel sides in this case is 5cm and 11cm, so that means your bases are 5&11. Your height is 4.
A=1/2(5+11)4
In order to do this you need to do the distributive property first.
1/2 x 5 = 2 1/2
1/2 x 11 = 5 1/2
Then next you need to do:
2 1/2 + 5 1/2 = 8
The last step is to do:
8 x 4 = 32
SO THE ANSWER IS 32.
5 0
3 years ago
Someone please help me out with this as soon as possible
Burka [1]
1/8..........,.......
8 0
3 years ago
How do I find the center &amp; radius, then write a standard equation for a,b, and c?
Ghella [55]

Firstly , we will locate centres and radius in the figures

(a)

We can see that

centre=(h,k)=(0,0)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-0)^2+(y-0)^2=5^2

x^2+y^2=25

(b)

We can see that

centre=(h,k)=(5,4)

radius=r=3

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-5)^2+(y-4)^2=3^2

(x-5)^2+(y-4)^2=9

(c)

We can see that

centre=(h,k)=(4,3)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-4)^2+(y-3)^2=5^2

(x-4)^2+(y-3)^2=25


5 0
3 years ago
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